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Lapatulllka [165]
2 years ago
3

A receiver is in a jet flying alongside another jet that is emitting 2.0 x 106 Hz radio waves. If the jets fly at 268 m/s, what

is the change in frequency detected at the receiver?
Physics
1 answer:
NNADVOKAT [17]2 years ago
3 0

Answer:

0 Hz as there is no relative moving between jets so there is no shift in the frequency.

Explanation:

The jet in which the receiver is present and the jet which is emitting the radio waves of frequency 2.0×10⁶ Hz are moving at same speed. Hence, between the two jets, there is no relative motion and thus , for one of the system , the other is at rest. <u>So, there will be no change in frequency as the radio waves receives the receiver with same frequency because there is no frequency shift.</u>

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Please find the answer in the explanation

Explanation:

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2 years ago
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How can controlling the way light bends and reflects be used to help people?
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2 years ago
An electric drill transfers 200 J of energy into a useful kinetic energy store. It also transfers 44 J of energy by sound and 48
kramer

Answer:

Er = 108 [J]

Explanation:

To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.

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2 years ago
A Porsche challenges a Honda to a 200-m race.Because the Porsche's acceleration of 3.5 m/s2 is larger than the Honda's 3.0 m/s2,
Blizzard [7]

Answer:

Honda won by 0.14 s

Explanation:

We are given that

Distance =S=200 m

Initial velocity of Honda=u=0m/s

Initial velocity of Porsche=u'=0m/s

Acceleration of Honda=3.0m/s^2

Acceleration of Porsche's=3.5m/s^2

Time taken by Honda  to start=1 s

s=ut+\frac{1}{2}at^2

Substitute the values

200=0(t)+\frac{1}{2}(3)t^2

200=\frac{3}{2}t^2

t^2=\frac{200\times 2}{3}=\frac{400}{3}

t=\sqrt{\frac{400}{3}}=11.55s

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Time =11.69-11.55=0.14 s

Honda won by 0.14 s

3 0
2 years ago
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