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stira [4]
1 year ago
9

What is the fi nal concentration of a 0.6 M NaCl solution if its volume is doubled and the number of moles of solute is tripled?

Chemistry
1 answer:
pshichka [43]1 year ago
4 0

Answer: The final concentration of solution will be 0.9 M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n}{V_s}

where,

n= moles of solute  

V_s = volume of solution in L

Given : molarity = 0.6 i.e. 0.6 moles are present in 1 L of solution.

Given: volume is doubled and moles are tripled

Thus moles = 0.6\times 3=1.8 moles

volume =1L\times 2= 2L

Molarity=\frac{1.8moles}{2L}=0.9M

Therefore, the final concentration of solution will be 0.9 M.

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Due to random assortment and incomplete dominance of alleles.

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2 years ago
How many moles of AgNO3 must react to form 0.854 mol Ag?
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The answer:
<span>The equation of its dissolution in water is: AgNO3 → Ag + (aq)  +  NO3- (aq)

and     </span>AgNO3 →   Ag + (aq)  +  NO3- (aq)
          1 mol          1mol                1mol 
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1 year ago
Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 669.1-g sam
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Answer:

2.4 ×10^24 molecules of the herbicide.

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We must first obtain the molar mass of the compound as follows;

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We know that one mole of a compound contains the Avogadro's number of molecules.

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169 g of the herbicide contains 6.02×10^23 molecules

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1 year ago
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