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OlgaM077 [116]
2 years ago
7

If two objects are electrically attracted to each other, 4) A) one object must be negatively charged and the other object must b

e positively charged. B) both objects must be positively charged. C) both objects must be negatively charged. D) the objects could be electrically neutral. E) None of the above statements are absolutely true. Answer: D
Physics
2 answers:
Jet001 [13]2 years ago
6 0

Answer : The correct option is, (E) None of the above statements are absolutely true.

Explanation :

As we know that, electric charge is carried by the subatomic particles. That means, negative charge is carried by electrons and positive charge is carried by protons.

There are two types of electric charge.

Positive charge

Negative charge

The positive charge is created when the number of protons are more than the number of electrons.

The negative charge is created when the number of electrons are more than the number protons.

As we know that like charges repel each other and unlike charges attract each other.

When one object is positively charged and another is negatively charged then there is some force of attraction between them. Thus, two objects are electrically attracted to each other.

But electric for of attraction also exist between charged object and neutral object.

Hence, correct option is, (E) None of the above statements are absolutely true.

Drupady [299]2 years ago
4 0

Answer:

option (a)

Explanation:

There are some properties of charge given as

(a) Charges are of two types: negative charge and positive charge.

(b) Like charges repel each other and unlike charges attract each other.

(c) charges are conserved in nature.

(d) charges are quarantined.

So, the two charges which are opposite in nature can only attract each other.

So, if there is one negative and one positive charge, they always attract each other.

The force of attraction or repulsion between the two charges is given by the Coulomb's law.

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The velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. What was the average acceleration?
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the acceleration is a=3ms^-2

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Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mu
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Answer:

Horizontal component: F_x = 58\ N

Vertical component: F_y = 33.5\ N

Explanation:

To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.

Therefore, for the horizontal component, we have:

F_x = F * cos(angle)

F_x = 67 * cos(30)

F_x = 58\ N

For the vertical component, we have:

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2 years ago
A 56 kg diver runs and dives from the edge of a cliff into the water which is located 4.0 m below. If she is moving at 8.0 m/s t
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Answer:

1) 2197.44 J

2) 0 J

3) 2197.44 J = Constant

4) 2197.44 J

5) Approximately 8.86 m/s

Explanation:

The given parameters are;

The mass of the diver, m = 56 kg

The height of the cliff, h = 4.0 m

The speed with which the diver is moving, vₓ = 8.0 m/s

The gravitational potential energy = Mass, m × Height of the cliff, h × Acceleration due to gravity, g

1) Her gravitational potential energy = 56 × 4.0 × 9.81 = 2197.44 J

2) The kinetic energy = 1/2·m·u²

Where;

u = Her initial velocity = 0 when she just leaves the cliff

Therefore;

Her kinetic energy when she just leaves the cliff = 1/2 × 56 × 0² = 0 J

3) The total mechanical energy = Kinetic energy + Potential energy

The total mechanical energy is constant

Her total mechanical energy relative to the water surface when she leaves the cliff = Her gravitational potential energy = 2197.44 J = Constant

4) Her total mechanical energy relative to the water surface just before she enters the water = 2197.44 J

5) The speed with which she enters the water, v, is given from, v² = u² + 2·g·h

Where;

u = The initial velocity at the top of the cliff before she jumps= 0 m/s

∴ v² = 0² + 2 × 9.81 × 4 = 78.48

v = √78.48 ≈ 8.86 m/s

The speed with which she enters the water, v ≈ 8.86 m/s

7 0
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