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AfilCa [17]
2 years ago
10

Which important change in electronic devices, such as televisions and computers, is a result of the use of metalloids as semicon

ductors?
A) Electronic devices have become smaller.
B) Electronic devices are now more brittle.
C) Electronic devices now use more energy.
D) Electronic devices have become more expensive.
Chemistry
2 answers:
nalin [4]2 years ago
8 0

Answer:

option A

Explanation:

correct answer is option A

metalloids are the substances which are not metal and also are not non-metal they have the property of both metals and non-metals.                                                  

metalloids example are silicon, Germanium, Arsenic (As) etc.

Usage of metalloids as semiconductor has  decreases the size of the circuits which leads to the shrink the size of many electronic devices such as TV, mobile etc.

scZoUnD [109]2 years ago
7 0

Answer:

Option (A) Electronic devices have become smaller.

Explanation:

Semiconductor devices are the devices which are based on the properties of the  semiconductor materials like  germanium, silicon, gallium and arsenide. The commonly used materials in electronic devices are the silicon and  germanium because of their low cut off voltages i.e 0.7 v and 0.3 v. Semiconductor materials made the electronic devices smaller as they replaced the Vacuum tubes which was bulky with high operating voltage, high power consumption.

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Wine has a pH of 3, which means it is __________ times more acidic than tomatoes, which have a pH of 4.
Natasha2012 [34]

Answer:

10

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

Thus, from the formula, more the concentration of the hydrogen ions or more the acidic the solution is, the less is the pH value of the solution.

Thus, solution with pH = 3 will be more acidic than solution with pH =4  

Thus, concentration of the [H⁺] when pH =3

3 = - log [H⁺]

[H⁺] = 10⁻³ M

For pH = 4, [H⁺] = 10⁻⁴ M

<u>hence, pH = 3 is 10 times more acidic than pH = 4</u>

5 0
2 years ago
Sulfurous acid is a diprotic acid with the following acid-ionization constants: Ka1 = 1.4x10−2, Ka2 = 6.5x10−8 If you have a 1.0
REY [17]

Answer:

pH = 7.1581

Explanation:

The equilibrium of NaHSO₃ with Na₂SO₃ is:

HSO₃⁻ ⇄ SO₃²⁻ + H⁺

<em>Where K of equilibrium is the Ka2: 6.5x10⁻⁸</em>

HSO₃⁺ reacts with NaOH, thus:

HSO₃⁻ + NaOH → SO₃²⁻ + H₂O + Na⁺

As the buffer is of 1.0L, initial moles of HSO₃⁻ and SO₃²⁻ are:

HSO₃⁻: 0.252 moles

SO₃²⁻: 0.139 moles

Based on the reaction of NaOH, moles added of NaOH are subtracting moles of HSO₃⁻ and producing SO₃²⁻. The moles added are:

0.0500L ₓ (1mol /L): 0.050 moles of NaOH.

Thus, final moles of both compounds are:

HSO₃⁻: 0.252 moles - 0.050 moles = 0.202 moles

SO₃²⁻: 0.139 moles + 0.050 moles = 0.189 moles

Using H-H equation for the HSO₃⁻ // SO₃²⁻ buffer:

pH = pka + log [SO₃²⁻] / [HSO₃⁻]

Where pKa is - log Ka = 7.187

Replacing:

pH = 7.187 + log [0.189] / [0.202]

<h3>pH = 7.1581</h3>

4 0
2 years ago
What is the molar mass of magnesium sulfate heptahydrate (MgSO4⋅ 7H2O) ?
KatRina [158]

Answer:

option D = 246 g/mol

Explanation:

Molar mass of MgSO₄⋅ 7H₂O:

Molar mass =  24.305 + 32.065 + 16×4 + 7 (1.008×2 +16)

Molar mass = 24.305 + 32.065 + 64 + 7 (18.016)

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7 0
2 years ago
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Setler79 [48]
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6 0
2 years ago
Consider a beaker of water sitting on the pan of an electronic scale that has been tared. A metal weight hanging from a string i
natka813 [3]

Answer:

See explanation below for answers

Explanation:

We know that the balance is tared, so the innitial weight would be zero. Now, let's answer this by parts.

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In this case all we need to do is to substract the 0.70 with the 0.13 g. so:

mW = 0.70 - 0.13

mW = 0.57 g of water

b) Volume of water.

In this case, we have the density of water, so we use the formula for density and solve for volume:

d = m/V

V = m/d

Replacing:

Vw = 0.57/0.9982

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c) volume of the metal weight

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d) the mass of the metal weight.

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e) density.

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d = 0.70 / 0.5710

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4 0
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