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Dahasolnce [82]
2 years ago
12

Two vectors, r and c, are equal: r = c. Which of the following statements are true? (Select all that apply.)

Physics
1 answer:
s344n2d4d5 [400]2 years ago
6 0

Answer:

(A) The y-component of r must be equal to the y-component of c

(B) The x-component of r must be equal to the x-component of c

(C) The z-component of r must be equal to the z-component of c

(F) The unit vector r must be equal to the unit vector c.

Explanation:

If two vectors are equal there are some conditions must be satisfy for the two vectors to be equal.

Let us suppose 2 vectors as,

A=a_{1}i+ a_{2}j+a_{3}k and

B=b_{1}i+ b_{2}j+b_{3}k

The conditions for the above two vectors should be equal are:

(1) a_{1}=b_{1}, a_{2}=b_{2}, and a_{3}=b_{3}.

(2) Unit vector of A must be equal to unit vector of B.

(3) Magnitude of both the vectors should be equal.

Now, according to question and observing above conditions of equality for r and c to be equal, the statements should be true are:

(A) The y-component of r should be equal to the y-component of c

(B) The x-component of r should be equal to the x-component of c

(C) The z-component of r should be equal to the z-component of c

(F) The unit vector r should be equal to the unit vector c.

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If you have to apply 40n of force on a crowbar to lift a rock that weights 400n, what is the actual mechanical advantage of the
Mrrafil [7]
The mechanical advantage is defined as the ratio between the force produced by a machine and the force applied in input:
MA= \frac{F_{out}}{F_{in}}
For the crowbar of the problem, the force applied in input is 40 N, while the force produced in output is equal to the weight of the rock that is lifted, so 400 N. Therefore, the mechanical advantage is
MA= \frac{400 N}{40 N}=10
3 0
2 years ago
A gas is compressed from 600 cm3 to 200cm3 at a constant pressure of 400 kpa. at the same time, 100 j of heat energy is transfer
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The initial volume of the gas is
V_i = 600 cm^3
while its final volume is
V_f = 200 cm^3
so its variation of volume is
\Delta V = V_f - V-i = 200 cm^3 - 600 cm^3 = -400 cm^3 = -400 \cdot 10^{-6} m^3

The pressure is constant, and it is
p=400 kPa = 400 \cdot 10^3 Pa

Therefore the work done by the gas is
W=p\Delta V = (400 \cdot 10^3 Pa)(-400 \cdot 10^{-6} m^3)=-160 J
where the negative sign means the work is done by the surrounding on the gas.

The heat energy given to the gas is
Q=+100 J

And the change in internal energy of the gas can be found by using the first law of thermodynamics:
\Delta U = Q-W = 100 J - (-160 J)=+260 J
where the positive sign means the internal energy of the gas has increased.
7 0
1 year ago
Investigators are exploring ways to treat milk for longer shelf life by using pulsed electric fields to destroy bacterial contam
Georgia [21]

Answer:

C = 3.77*10⁻¹⁰ F = 377 pF

Q = 1.13*10⁻⁵ C

Explanation:

Given

D = 8.0 cm = 0.08 m

d = 0.95 cm = 0.95*10⁻² m

k = 80.4  (dielectric constant of the milk)

V = 30000 V

C = ?

Q = ?

We can get the capacitance of the system applying the formula

C = k*ε₀*A / d

where

ε₀ = 8.854*10⁻¹² F/m

and   A = π*D²/4 = π*(0.08 m)²/4

⇒  A = 0.00502655 m²

then

C = (80.4)*(8.854*10⁻¹² F/m)*(0.00502655 m²) / (0.95*10⁻² m)

⇒  C = 3.77*10⁻¹⁰ F = 377 pF

Now, we use the following equation in order to obtain the charge on each plate when they are fully charged

Q = C*V

⇒  Q = (3.77*10⁻¹⁰ F)*(30000 V)

⇒  Q = 1.13*10⁻⁵ C

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2 years ago
Identifying the target population or target audience occurs during which step of the engineering design loop A identified the ne
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C I believe is the correct answer. Developing possible solutions would be easier than spending hours researching or identifying the need.
4 0
2 years ago
When the mass of the bottle is 0.125 kg, the KE is______ kg m2/s2.
tensa zangetsu [6.8K]
Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
(3) KE = 3 kg m^2/s^2
(4) KE = 4 kg m^2/s^2


Explanation:

(1) Given mass = 0.125 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.125 * (16)
KE = 1 kg m^2/s^2

(2) Given mass = 0.250 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.250 * (16)
KE = 2 kg m^2/s^2

(3) Given mass = 0.375 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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KE = (1/2) * 0.375 * (16)
KE = 3 kg m^2/s^2

(4) Given mass = 0.500 kg
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Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
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KE = (1/2) * 0.5 * (16)
KE = 4 kg m^2/s^2
5 0
2 years ago
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