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1 year ago

The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 4.96 mm?

Chemistry

2 answers:

nikitadnepr [17]1 year ago

4 0

Answer:

4960000000 pm

Explanation:

4.96*1000000000= 4960000000

djverab [1.8K]1 year ago

3 0

Answer:

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is $1.6644\times 10^7$ atoms.

Explanation:

The radius of a uranium atom ,r = 149 pm = $1.49\times 10^{-7} mm$

$1 pm=10^{-9} mm$

The diameter of a uranium atom ,d =

d = 2r = $2\times 1.49\times 10^{-7} mm=2.98\times 10^{-7} mm$

The let the uranium atom to be laid side by side to span a distance of 4.96 mm be x.

$x\times d=4.96 mm$

$x=\frac{4.96 mm}{d}=\frac{4.96 mm}{2.98\times 10^{-7} mm}=1.6644\times 10^7$ atoms.

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is $1.6644\times 10^7$ atoms.

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Silver is often extracted from ores such as k[ag(cn)2] and then recovered by the reaction 2k ⎡ ⎣ag(cn)2 ⎤ ⎦(aq) + zn(s) ⟶ 2ag(s)

lions [1.4K]

Take note of the whole number beside each substance in the reaction because these will be used in the stoichiometric calculations below:

Molar mass of <span>k[ag(cn)2]:199 g/mol
Molar mass of Zn(Cn)2: 117.44 g/mol
Avogadro's number: 6.022</span>×10²³ molecules/mol

a.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(6.022×10²³ molecules/mol) = <em>5.34×10²² molecules of Zn(Cn)₂</em>

b.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(117.44 g/mol) = <em>10.41 g of Zn(Cn)₂</em>

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2 years ago

as a 15.1-gram sample of a metal absorbs 48.75 j of heat its temperature increases 25.0 k what is the specific heat capacity of

Leviafan [203]

Specific heat capacity (c) of a material is related to the Energy Absorbed (Q), mass of the material (m) and the change in temperature (T) by the following equation:

$c= \frac{Q}{mT}$

Substituting the values of Q, m and T in the above equation, we get:

$c= \frac{48.75}{15.1*25}=0.129$

So the specific heat capacity of the metal with given conditions will be 0.129 J/g.K

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1 year ago

What term refers to the coldest and densest zone, deep below the surface of a lake?

uranmaximum [27]

Profundal

profundal zone is the coldest and deepest zone

5 0

1 year ago

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For double-helix formation, change in Gibbs free energy, ΔG, can be measured to be −54 kJ⋅mol−1 (−13 kcal⋅mol−1) at pH 7.0 in 1

77julia77 [94]

Answer:

Explanation:

Entropy change in the system : --

ΔG = −54 kJ⋅mol−1 (−13 kcal⋅mol−1) = −54 kJ⋅mol−1 (−13 x 4.2 kJ⋅mol−1)

= - 108.6 KJ / mol

ΔH = -251 kJ/mol (-60 kcal/mol) = -251 kJ/mol (-60 x 4.2 kJ/mol)

= - 503 KJ / mol

ΔG = ΔH - TΔS

ΔS = ( ΔH - ΔG ) / T

= - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹

= - 1323.48 J / mol k⁻¹

Entropy change in the surrounding

+ 1323.48 J / mol k⁻¹

7 0

1 year ago

When the pressure that a gas exerts

Savatey [412]

<h2>Hello!</h2>

The answer is:

When the pressure that a gas exerts on a sealed container changes from

22.5 psi to 19.86 psi, the temperature changes from 110°C to

65.9°C.

To calculate which is the last pressure, we need to use Gay-Lussac's law.

The Gay-Lussac's Law states that when the volume is kept constant, the temperature (absolute temperature) and the pressure are proportional.

The Gay-Lussac's equation states that:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

We are given the following information:

We need to remember that since the temperatures are given in Celsius degrees, we need to convert it to Kelvin (absolute temperature) before use the equation, so:

$P_1=22.5Psi\\T_1=110\°C=110\°C+273.15=383.15K\\T_1=65.9\°C=65\°C+273.15=338.15K$

Now, calculating we have:

$\frac{P_1}{T_1}*(T_2)=P_2\\\\P_2=\frac{P_1}{T_1}*(T_2)=\frac{22.5Psi}{383.15}*338.15=19.86Psi$

Hence, the final pressure is equal to 19.86 Psi.

Have a nice day!

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1 year ago

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