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2 years ago

The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 4.96 mm?

Chemistry

2 answers:

nikitadnepr [17]2 years ago

4 0

Answer:

4960000000 pm

Explanation:

4.96*1000000000= 4960000000

djverab [1.8K]2 years ago

3 0

Answer:

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is $1.6644\times 10^7$ atoms.

Explanation:

The radius of a uranium atom ,r = 149 pm = $1.49\times 10^{-7} mm$

$1 pm=10^{-9} mm$

The diameter of a uranium atom ,d =

d = 2r = $2\times 1.49\times 10^{-7} mm=2.98\times 10^{-7} mm$

The let the uranium atom to be laid side by side to span a distance of 4.96 mm be x.

$x\times d=4.96 mm$

$x=\frac{4.96 mm}{d}=\frac{4.96 mm}{2.98\times 10^{-7} mm}=1.6644\times 10^7$ atoms.

Uranium atoms required to be laid side by side to span a distance of 4.96 mm is $1.6644\times 10^7$ atoms.

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The name "penicillin" is used for several closely-related antibiotics. A 1.2177 g sample of one of these compounds is burned, pr

masya89 [10]

Answer: The empirical formula for the given organic compound is $C_7H_{11}O_2SN$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$S_vN_wC_xH_yO_z+O_2\rightarrow CO_2+H_2O+SO_2+NO$

where, 'v', 'w' 'x', 'y' and 'z' are the subscripts of sulfur, nitrogen, carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=0.2829g$

Mass of $H_2O=0.1159g$

Mass of $SO_2=0.4503g$

Mass of NO = 0.2109 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

Molar mass of sulfur dioxide = 64 g/mol

Molar mass of nitrogen monoxide = 30 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 2.1654 g of carbon dioxide, $\frac{12}{44}\times 2.1654=0.590g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.6965 g of water, $\frac{2}{18}\times 0.6965=0.077g$ of hydrogen will be contained.

For calculating the mass of sulfur:

In 64 g of sulfur dioxide, 32 g of sulfur is contained.

So, in 0.4503 g of sulfur dioxide, $\frac{32}{64}\times 0.4503=0.225g$ of sulfur will be contained.

For calculating the mass of nitrogen:

In 30 g of nitrogen monoxide, 14 g of nitrogen is contained.

So, in 0.2109 g of nitrogen monoxide, $\frac{14}{30}\times 0.2109=0.098g$ of nitrogen will be contained.

Mass of oxygen in the compound = (1.2177) - (0.590 + 0.077 + 0.225 + 0.098) = 0.2277 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.590g}{12g/mole}=0.049moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.077g}{1g/mole}=0.077moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.2277g}{16g/mole}=0.0142moles$

Moles of Sulfur = $\frac{\text{Given mass of Sulfur}}{\text{Molar mass of sulfur}}=\frac{0.225g}{32g/mole}=0.007moles$

Moles of Nitrogen = $\frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.098g}{14g/mole}=0.007moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.007 moles.

For Carbon = $\frac{0.049}{0.007}=7$

For Hydrogen = $\frac{0.077}{0.007}=11$

For Oxygen = $\frac{0.0142}{0.007}=2.03\approx 2$

For Sulfur = $\frac{0.007}{0.007}=1$

For Nitrogen = $\frac{0.007}{0.007}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O : S : N = 7 : 11 : 2 : 1 : 1

Hence, the empirical formula for the given compound is $C_7H_{11}O_2S_1N_1=C_7H_{11}O_2SN$

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2 years ago

Which of these is a trace fossil : shrimp burrow, seashell, dinosaur egg, shark tooth

Artyom0805 [142]

Answer:

Option (1)

Explanation:

Trace fossils are defined as those traces such as the impressions and signs of ancient remains of an organism, that are found over relatively softer sediment.

These play a very important role in the field of paleontology as it provides information about the ancient organism that lived in the past in a particular location.

Some of the examples of trace fossils are track and trails, burrows, footprints, cast and mold.

Shrimp burrows are an example of trace fossils, which are made by the marine organisms named shrimps, that are usually found at the bottom of the ocean.

Thus, the correct answer is option (1).

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2 years ago

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2 years ago

Given six molecules, identify the molecules with polar bonds and the molecules that are polar.CCl4, CH3Cl, H20, CO2, O2

Nikitich [7]

Answer:

Non-polar compounds: $CCl_4$ , $O_2$ , $CO_2$

Polar compounds: $CH_3Cl$ , $H_2O$

Explanation:

For this question, we must start with the Lewis structure for each molecule and then we can do their respective analysis:

-) $CCl_4$

In this case, we have 4 equal atoms attached to the central atom. Therefore, we have the same magnitude of electronegativity. Chlorine atoms have different and opposite directions. Therefore due to the orientation the dipole moments cancel and the net dipole moment will be zero and the molecule will be non-polar.

-) $O_2$

In this case, we have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the opposite. Therefore the dipole moments are canceled and the molecule will be non-polar.

-) $CO_2$

In this case, we also have a linear structure in which the magnitude of the dipole moment is the same, but the direction is the opposite. Therefore the dipole moments are canceled and the molecule will be non-polar.

-) $CH_3Cl$

For this molecule, we have a different atom. The hydrogen atom, therefore the magnitude of one of the atoms attached to the central atom is different and the magnitude of the net dipole moment will be different from zero and the molecule will be polar.

-) $H_2O$

For this molecule, due to the structure of the molecule, the dipole moments of oxygens will not have a totally opposite configuration. Therefore, the net dipole moment will be different from zero and the molecule will be polar.

See figure 1 to further explanations

I hope it helps!

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2 years ago