Answer: The correct answer is "Mechanical waves can apply pressure to and push on objects in their path".
Explanation:
Mechanical wave is wave in which there is an oscillation of the wave. The energy is transferred through a medium. Mechanical waves can apply pressure to and push on their path. Only the energy is transferred not the matter.
Mechanical waves are of three types: Transverse wave, Longitudinal wave and Surface wave. The examples of the mechanical wave are sound wave and water wave.
Sound is a pressure disturbance which travels through a medium. It consists of compression and rarefaction.
The mechanical waves need a medium for their propagation. They travel faster in denser medium.
Therefore, the correct option is (B).
Explanation:
Average atomic mass of the vanadium = 50.9415 amu
Isotope (I) of vanadium' s abundance = 99.75 %= 0.9975
Atomic mass of Isotope (I) of vanadium ,m= 50.9440 amu
Isotope (II) of vanadium' s abundance =(100%- 99.75 %) = 0.25 % = 0.0025
Atomic mass of Isotope (II) of vanadium ,m' = ?
Average atomic mass of vanadium =
m × abundance of isotope(I) + m' × abundance of isotope (II)
50.9415 amu =50.9440 amu× 0.9975 + m' × 0.0025
m'= 49.944 amu
The atomic mass of isotope (II) of vanadium is 49.944 amu.
Using the Equation: PV=nRT
Where P is the pressure 60 cmHg or 600 mmHg or 600/760= 0.789 atm
V is the volume 125 ml or 0.125 L, n is the number of moles, R is a constant 0.082057, and T is temperature 25 °C or 298 K;
Therefore:
0.789 × 0.125 = n × 0.082057 × 298
n = 0.0987/24.45
= 0.004036 mol
0.004036 mole has a mass of 0.286 g
Hence; 1 mole has a mass of 0.286/0.004036
= 70.8 g /mol
Therefore the molar mass of the gas is 71 g/mol (2 sfg)
Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq= 
=14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5= 
14.5 x (0.15 M) x 
= (CH₃OH)
0.2818 M = (CH₃OH)
<span>Sugar is not soluble in Oil so it coagulated when Joyce added sugar to oil.
But sugar is soluble in water so when Joyce added water in the mixture of OIl and Sugar and then shaked it the sugar dissolved in the water.Leaving no traces behind.As Oil is hydrophobic it doesn't mix with water instead it floats on top.So by using the solubility of sugar in water Joyce separated sugar from oil</span>
