While you are studying for an upcoming physics exam, a lightning storm is brewing outside your window. Suddenly, you see a tree
1 answer:
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Answer:
ω2 = 216.47 rad/s
Explanation:
given data
radius r1 = 460 mm
radius r2 = 46 mm
ω = 32k rad/s
solution
we know here that power generated by roller that is
power = T. ω ..............1
power = F × r × ω
and this force of roller on cylinder is equal and opposite force apply by roller
so power transfer equal in every cylinder so
( F × r1 × ω1) ÷ 2 = ( F × r2 × ω2 ) ÷ 2 ................2
so
ω2 =
ω2 = 216.47
Answer:
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
0.010935 J
0.0858675 J
Explanation:
= Mass of first glider = 0.3 kg
= Mass of second glider = 0.15 kg
= Initial Velocity of first glider = 0.8 m/s
= Initial Velocity of second glider = 0 m/s
= Final Velocity of first glider
= Final Velocity of second glider
As momentum and Energy is conserved
From the two equations we get
The final velocity of the first glider is 0.27 m/s in the same direction as the first glider
The final velocity of the second glider is 1.07 m/s in the same direction as the first glider.
Kinetic energy is given by
Final kinetic energy of first glider is 0.010935 J
Final kinetic energy of second glider is 0.0858675 J