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2 years ago

3Ni2+(aq)+2Co(s)⟶2Co3+(aq)+3Ni(s) Which substance gets oxidized?

Chemistry

1 answer:

forsale [732]2 years ago

7 0

Answer:

Co⁰ - 3e⁻ → Co³⁺ (cobalt loses electrons so it is oxidized)

Explanation:

When a substance is oxidized it means that it loses electrons.

When a substance is reduced it means that it gains electrons.

Ni²⁺ + 2e⁻ → Ni⁰ (nickel gains electrons so it is reduced)

Co⁰ - 3e⁻ → Co³⁺ (cobalt loses electrons so it is oxidized)

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Which statements about reducing sugars are true? D‑Glucose (an aldose) is a reducing sugar. The oxidation of a reducing sugar fo

qaws [65]

Answer:

The true statements are given below.

Explanation:

1 D glucose is a reducing sugar

2 The oxidation of reducing sugar forms a carboxylic acid sugar.

D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.

The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).

4 0

2 years ago

Calculate the molar mass of a 2.89 g gas at 346 ml, a temperature of 28.3 degrees Celsius, and a pressure of 760 mmHg.

malfutka [58]

The molar mass of gas = 206.36 g/mol

<h3>Further explanation</h3>

In general, the gas equation can be written

$\large{\boxed{\bold{PV=nRT}}}$

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.082 l.atm / mol K

T = temperature, Kelvin

mass (m)= 2.89 g

volume(V) = 346 ml = 0.346 L

T = 28.3 C + 273 = 301.3 K

P = 760 mmHg=1 atm

The molar mass (M) :

$\tt PV=\dfrac{m}{M}RT\\\\M=\dfrac{mRT}{PV}\\\\M=\dfrac{2.89\times 0.082\times 301.3}{1\times 0.346}\\\\M=206.36~g/mol$

8 0

2 years ago

Compute the end-to-end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule with a number-

MArishka [77]

Answer:

5156 Â

Explanation:

Chains of monomers that are being linked together constitute what is called polymers. in this question; we are to compute the end to end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule.

Using the following approach:

The first step is to determine the repeating units in polymer

The number of repeating unit = average molecular weight/ atomic weight of PVC

Given that:

average molecular weight = 256,131 g/mol

atomic weight of PVC = 62.498 g

Then;

The number of repeating unit = 256,131 g/mol / 62.498 g = 4098.227143 mol

Now the distance is calculated by using the formula:

d = (C-C) × sin 109.5/2

C-C bond length = 1.54 angstroms

tetrahedral bond angle = 109.5°

Then d = (1.54) × sin 109.5/2

d = 1.258

Thus ; the end to end separation is :

4098.227143 × 1.258 = 5155.57 Â

The answer is 5156 Â (since no decimal should be included )

6 0

2 years ago

How many mm are equal to 4.75 x 10-2 m?

kherson [118]

Answer:

47.5 mm

Explanation:

5 0

2 years ago

The nucleus of an atom is dense and positively charged. What was observed when positively charged particles were radiated onto a

ankoles [38]

<span>According to my knowledge, I feel the answer is -
Particles that struck the center of the atom were repelled.

Hope this helps!
</span>

8 0

2 years ago

Read 2 more answers