Answer:
<em>The final charge on the 6.0 mF capacitor would be 12 mC</em>
Explanation:
The initial charge on 4 mF capacitor = 4 mf x 50 V = 200 mC
The initial Charge on 6 mF capacitor = 6 mf x 30 V =180 mC
Since the negative ends are joined together the total charge on both capacity would be;
q = 
q = 200 - 180
q = 20 mC
In order to find the final charge on the 6.0 mF capacitor we have to find the combined voltage
q = (4 x V) + (6 x V)
20 = 10 V
V = 2 V
For the final charge on 6.0 mF;
q = CV
q = 6.0 mF x 2 V
q = 12 mC
Therefore the final charge on the 6.0 mF capacitor would be 12 mC
Answer:
v = 54.2 m / s
Explanation:
Let's use energy conservation for this problem.
Starting point Higher
Em₀ = U = m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
m g h = ½ m v²
v² = 2gh
v = √ 2gh
Let's calculate
v = √ (2 9.8 150)
v = 54.2 m / s
Answer:
The displacement of the spring due to weight is 0.043 m
Explanation:
Given :
Mass 
Kg
Spring constant 
According to the hooke's law,
Where 
force, 
displacement
Here,
( 
)
N
Now for finding displacement,
Here minus sign only represent the direction so we take magnitude of it.
m
Therefore, the displacement of the spring due to weight is 0.043 m
<span>The chemical formula for the unknown gas is Ne.
Since we're looking for the rate at which a gas escapes through a small hole, we're dealing with effusion. For effusion, the rate is proportional to the velocity of the gas particles.
Kinetic energy
E = 0.5 mv^2
Since the kinetic energy of individual gas particles is the same if their temperatures are the same, we can create the following equality:
0.5 m1(v1)^2 = 0.5 m2(v2)^2
Double each side to make it simplier.
m1(v1)^2 = m2(v2)^2
Divide both sides by m1 and by (v2)^2, giving
(v1)^2/(v2^2) = m2/m1
And take the square root, giving
(v1)/(v2) = sqrt(m2/m1)
Now let's use the value 1 and the atomic weight of Kr for v1 and m1
1/(v2) = sqrt(m2/83.798)
And for v2, we'll use the value 2.04
1/2.04 = sqrt(m2/83.798)
Now solve for m2.
1/2.04 = sqrt(m2/83.798)
1/4.1616 = m2/83.798
83.798/4.1616 = m2
20.13600538 = m2
So the atomic weight of the unknown gas should be close to 20.136. Looking at a periodic table, I find that neon has an atomic weight of 20.18 which is quite close. Additionally, since neon is a noble gas, its gas particles consist of individual atoms. So the unknown gas is neon.</span>
When the surface of the comb rubs on your hair, the comb is electrically charged. When the comb comes close to the paper, the charge on the comb causes charge separation on the paper bits. Since paper is neutral, positive and negative charges are equivalent. The charge on the comb charges the area of the bit of paper nearest the comb to the opposite. Thus, the bits of paper become attracted to the comb.
