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Arlecino [84]
2 years ago
7

A gas made up of atoms escapes through a pinhole 2.04 times as fast as kr gas. write the chemical formula of the gas.

Physics
2 answers:
levacccp [35]2 years ago
6 0
<span>The chemical formula for the unknown gas is Ne. Since we're looking for the rate at which a gas escapes through a small hole, we're dealing with effusion. For effusion, the rate is proportional to the velocity of the gas particles. Kinetic energy E = 0.5 mv^2 Since the kinetic energy of individual gas particles is the same if their temperatures are the same, we can create the following equality: 0.5 m1(v1)^2 = 0.5 m2(v2)^2 Double each side to make it simplier. m1(v1)^2 = m2(v2)^2 Divide both sides by m1 and by (v2)^2, giving (v1)^2/(v2^2) = m2/m1 And take the square root, giving (v1)/(v2) = sqrt(m2/m1) Now let's use the value 1 and the atomic weight of Kr for v1 and m1 1/(v2) = sqrt(m2/83.798) And for v2, we'll use the value 2.04 1/2.04 = sqrt(m2/83.798) Now solve for m2. 1/2.04 = sqrt(m2/83.798) 1/4.1616 = m2/83.798 83.798/4.1616 = m2 20.13600538 = m2 So the atomic weight of the unknown gas should be close to 20.136. Looking at a periodic table, I find that neon has an atomic weight of 20.18 which is quite close. Additionally, since neon is a noble gas, its gas particles consist of individual atoms. So the unknown gas is neon.</span>
GrogVix [38]2 years ago
6 0

Gas consisting of atoms exits through the eye of a needle 2.04 times faster than Kr gas. The chemical formula of the gas must be determined.

Rate1/Rate2 = square root M1/M2

\frac{Rate1}{Rate2}

<h2>Further explanation</h2>

Graham's law reveals the relationship between the level of effusion or diffusion and the molar mass of a gas. Diffusion describes the spread of gas throughout the second volume of gas, while effusion describes the movement of gas through a small hole into an open space.

Chemical Problems Graham Law

One way to apply Graham's law is to determine whether one gas will have an effect faster or slower than the others and to quantify the rate difference.

For example, if you want to compare the effusion rates of hydrogen gas (H 2) and oxygen gas (O 2), you use the molar mass of gas (2 for hydrogen and 32 for oxygen, which is the atomic mass multiplied by 2 because each molecule contains two-atom) and connect it in reverse:

rate H 2 / rate O 2 = 32 1/2 / 2 1/2 = 16 1/2 / 1 1/2 = 4/1

So, hydrogen gas molecules produce four times faster than oxygen molecules.

Another type of Graham legal problem might require you to find the molecular weight of a gas if you know the identity of one gas and the ratio between the effusion levels of two gases is known.

M 2 = M 1 Rate 1 2 / Rate 2 2

Learn more

Graham's Effusion Law brainly.com/question/3903505

Chemical Formula brainly.com/question/6951261

Details

Class: College

Subject:  Physics

Keywords: Atoms, Chemical, Formula

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nexus9112 [7]

Answer: Dalton’s model

Explanation:

In the attached image we can see four atomic models labeled with four letters:

W represents the current and accepeted atomic model: a nucleus with an electron cloud, where the orbit and position of the electrons around the nucleus is defined by specific regions (associated with specific energy levels) where there is a greater probability of finding the electron at any given moment. It is important to note this model was improved by the works in quantum physics done by Louis de Broglie and Erwin Schrodinger.

X represents Rutherford's model (This model was proposed after Thomson's model). Ernest Rutherford conducted a series of experiments in order to corroborate Thomson's atomic model. However the results of the experiment led him to find out there is a concentration of charge in the atom's core (which was later called nucleus) surrounded by electrons.  This lead to a new atomic model, in which the atom has a positive charged nucleus surrounded by negative charged particles that move similar to the orbit of the planet around the Sun.

Y represents Thomson's model, also called  the <em>plum pudding</em> model. This scientific found out that atoms contain small subatomic particles with a negative charge (later called electrons). However, taking into consideration that at that time there was still no evidence of the atom nucleus, Thomson thought the electrons were immersed in the atom of positive charge that counteracted the negative charge of the electrons. Just like the raisins embedded in a pudding or bread.

Z represents Bohr's model. This model was proposed by the danish physicist Niels Bohr after Rutherford's model. In fact, this model was Rutherford's model with the following addition: electrons orbit the nucleus (like planets around the sun) in specific orbits at different energy levels around the nucleus.

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4 0
2 years ago
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An apple is whirled round in a horizontal circle on the end of a string which is tied to the stalk. It is whirled faster and fas
Brrunno [24]

when the apple moves in a horizontal circle, the tension force in the string provides the necessary centripetal force to move in circle. the tension in the string is given as

T=mv²/r

where T = tension force in the string , m = mass of the apple

v = speed of apple , r = radius of circle.

clearly , tension force depends on the square of the speed. hence greater the speed, greater will be the tension force.

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6 0
2 years ago
The net force on a boat causes it to accelerate at 1.55 m/s2. The mass of the boat is 215 kg. The same net force causes another
jekas [21]

Answer:

2666 kg

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Explanation:

m = Mass of boat

a = Acceleration of boat

From Newton's second law

Force

F=ma\\\Rightarrow F=215\times 1.55\\\Rightarrow F=333.25\ N

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F=ma\\\Rightarrow m=\frac{F}{a}\\\Rightarrow m=\frac{333.25}{0.125}\\\Rightarrow m=2666\ kg

Hence, mass of the second boat is 2666 kg

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What was the vertical component of her acceleration during push-off? the positive direction is upward?
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The weight of a bucket is 186 N. The bucket is being raised by two ropes. The free-body diagram shows the forces acting on the b
amm1812
Fnet=(115+106)-186= 34 N

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a=fnet/mass => 34N/18.98kg = 1.79 m/s^2

so A= 1.8m/s^2
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