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2 years ago

A patient is receiving 3000 mL/day of a solution that con-

Chemistry

1 answer:

frutty [35]2 years ago

5 0

Answer:

600 kCal/ day

Explanation:

You can solve this type of problems using proportions, with the rule of three.

Follow these steps:

1. Analyze the giving data

2. Organize it

3.Write the proportions

4. Clear the value you are looking for

5. Solve the equations by multiplying or dividing

Now for the exercise:

You have the following data:

3000 mL Solution per 1 day ----> 3000 mL S

The concentration of the solution is

5 g of dextrose per 100 mL Solution ----> 5g D - 100 mL S

The glucose provides some specific energy

4 kCal per 1 g of dextrose ----> 4kCal - 1 g D

First find the total grams of dextrose (glucose) given in one day.

3000 mL S - x g D?

100 mL S - 5 g D

The grams of glucose given in one day

xg D? = 3000 mL S(5 g D)/100 mL S

you also can cancel the units mL S

xg D? = 150 g D.

Answer: The grams given in one day of glucose are 150 g /day

Now find the total Energy in those grams:

4 kCal - 1 g D

x kCal?-150 g D

Clear x kCal?

x kCal? = 4kCal (150g D)/(1g D)

x kCal? = 600 kCal remember is for one day!

so the answer is

The patient is receiving 600 kCal/day

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2 years ago

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trapecia [35]

Answer:

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Explanation:

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2 years ago

A sample from solution a and solution b were each tested with blue colored glucose indicator solution before the solutions were

vova2212 [387]

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2 years ago

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