Anne is working on a research project that involves the use of a centrifuge. Her samples must first experience an acceleration o
1 answer:
Answer:
The final rotation is 2.449 times the initial rotation
Explanation:
Centripetal acceleration and rotation speed of particle is related as
a=rω²
where ω is angular speed and r radius of circle
Rearranging equation
ω=
The initial acceleration is given by
a₁ =100g
The final acceleration of particle is
a₂ = 6 (100g)
=600g
The final and initial rotation speed are related as
ω2=
ω2=2.449ω1
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The man ran <u>4252.5 meters.</u>
Why?
To solve the problem, we need to divide the exercise into two movements, the first on while the was running at 4.5 m/s for 15 min, and then, while he was slowing down (going up because of the hill).
First movement: Running at 4.5 m/s for 15 min.
We need convert from minutes to seconds,
Now, calculating the distance covered for the first movement, we have:
So, we know that the man covered 4050m for the first movement, it will be our initial position for the second movement.
Second movement: acceleration -0.05m/s^2 (because he's slowing down) for 90 seconds, at 4.5m/s.
Hence, we have that he ran 4252.5 m.
Have a nice day!
Answer:
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
velocity = 7.26 * 10^6 m/sec
Explanation:
The rule that is used to solve this problem is shown in the attached image.
The variables are as follows:
k = 8.99 * 10^9 Nm^2 / C^2
e is the electron charge = -1.6 * 10^-19 C
q is the charge given = 1 * 10^-9 C
m is the mass of the electron = 9.11 * 10^-31
r1 is the radius of starting point = 3 cm = 0.03 m
r2 is the radius of the sphere = 2 cm = 0.02 m
Substitute with the givens in the equation to get the value of the velocity
Hope this helps :)
Answer:
second force = 32.784
Magnitude =
θ = -90°
Explanation:
a)
Fnet = ma
F1 + F2 = ma
20N + F2 = 2(12 × cos30° + 12 ×sin30°)
F2 = 2 × 12 ( sin 30° + cos 30°)
= 24 × ( 1 + √3 )÷ 2
=12 (1 +√3 )
= 32.784
b)
=
=
=
c)
θ = 30° + 180°
θ = 210°
210° - 300°
θ = -90°