Density of a substance is defined as the mass of the substance divided by the volume.
Density of the substance= 0.242 g cm⁻³
volume of the substance= 2.50 in³
As, 1 in³= 16.39 cm³
So, 2.50 in³= 16.39× 2.50 cm³=40.97 cm³
As ,
Mass=volume ×Density
Mass=40.97 × 0.242
Mass=9.916 g.
Check the attached file for the answer.
Answer:
d. One single bond and two double bonds.
Explanation:
The octate rule is a chemical rule in which the atoms prefer to have eight electrons in the valence shell. Where a single bond provide two electrons and a double bond provide 4 electrons. Thus:
a. Two double bonds
. Two double bonds provide 8 electrons. Octate rule <em>is not </em>violated
b. Three single bonds and one pair of electrons
. Three single bonds provide 6 electrons and one pair of electrons provide two electrons. Thus, you have eight electrons and octate rule <em>is not</em> violated
c. Two single bonds and one double bond
. Two single bonds provide four electrons and one double bond 4. Thus, you have eight electrons and octate rule <em>is not </em>violated.
d. One single bond and two double bonds. One single bond provides two electrons and two double bonds 8. Thus, you have 10 electrons and <em>octate rule is violated.</em>
e. Four single bonds. Four single bonds provide 8 electrons. Octate rule<em> is not </em>violated.
I hope it helps!
Answer: 2.7moles
Explanation:
6Cs + Fe2(CO3)3 —> 3Cs2CO3 + 2Fe
From the equation,
6moles of Cs produced 3 moles of Cs2CO3.
Therefore, 5.34 moles of Cs will produce = (5.4x3)/6 = 2.7moles of Cs2CO3
Answer:
k = ![\frac{[HOCl]^2}{[Cl]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHOCl%5D%5E2%7D%7B%5BCl%5D%5E2%7D)
Explanation:
The equilibrium-constant expression is defined as the ratio of the concentration of products over concentration of reactants. Each concentration is raised to the power of their coefficient.
Also, pure solid and liquids are not included in the equilibrium-constant expression because they don't affect the concentration of chemicals in the equilibrium
The global reaction is:
2 HgO (s) + H₂O (l) +2 Cl₂ (g) ⇌ 2 HOCl (aq) + HgO⋅HgCl₂ (s)
Thus, equilibrium-constant expression is:
<em>k = </em>
You don't include HgO nor HgO⋅HgCl₂ because are pure solids nor water because is pure liquid.
I hope it helps!
