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77julia77 [94]
1 year ago
12

identify the element in period 3 that requires the least amount of energy to remove the most loosely held electrons from a mole

of gaseous atoms of the element in the ground state.
Chemistry
1 answer:
OLga [1]1 year ago
3 0

Answer:

The element is Na

Explanation:

Ionization energy is the energy needed to release the last electron from an atom in its ground state to the gaseous state.  It is a periodic property that increases as we go through the periods of the periodic table, but decreases if we move in groups.  Sodium has thr ionic radius (another periodic property) that is too large, making it easier to release the electron away, since it is too far from the nucleus.

You might be interested in
Two nonpolar organic liquids, hexane (C6H14) and heptane (C7H16), are mixed. Do you expect ΔHsoln to be a large positive number,
Aliun [14]

Answer:

ΔH of solution is expected to be close to zero.

Explanation:

When we mix two non polar organic liquids like hexane and heptane,the resulting mixture formed is an ideal solution.An ideal solution is formed when the force of attraction between the molecules of the two liquids is equal to the force of attraction between the molecules of the same type.

For instance if liquids A and B are mixed,

F_{A-A} = F_{B-B} = F_{A-B}

Hence the condition before and after mixing remains unchanged.

Since enthalpy change is associated with inter molecular force of attraction the enthalpy change for ideal solution is zero.

More examples of ideal solutions are:

1. Ethanol and Methanol

2. Benzene and Toluene

3. Ethyl bromide and Ethyl iodide

5 0
2 years ago
40pionts
Pachacha [2.7K]

Problem One (left)

This is just a straight mc deltaT question

<em><u>Givens</u></em>

m = 535 grams

c = 0.486 J/gm

tf = 50

ti = 1230

Formula

E = m * c * (ti - tf)

Solution

E = 535 * 0.486 * ( 1230 - 50)

E = 535 * 0.486 * (1180)

E = 301077

Answer: A

Problem Two

This one just requires that you multiply the two numbers together and cut it down to 3 sig digits.

E = H m

H = 2257 J/gram

m = 11.2 grams

E = 2257 * 11.2

E = 25278  to three digits is 25300 Joules. Anyway it is the last one.

Three

D and E are both incorrect for the same reason. The sun and stars don't contain an awful lot of Uranium (1 part of a trillion hydrogen atoms). It's too rare. The other answers can all be eliminated because U 235 is pretty stable in its natural state. It has a high activation complex.

Your best chance would be enriched Uranium (which is another way of saying refined uranium). That would be the right environment. Atomic weapons and nuclear power plants (most) used enriched Uranium. You can google "Little Boy" if you want to know more.

Answer: B

Four

The best way to think about this question is just to get the answer. Answer C.

A: incorrect. Anything sticking together implies a larger and larger result. Gases don't work that way. They move about randomly.

B: Wrong. Heat and Temperature especially depend on movement. Stopping is not permitted. If a substance's molecules stopped, the substance would experience an extremely uncomfortable temperature drop.

C: is correct because the molecules neither stop nor do they stick. The hit and move on.

D: Wrong. An ax splitting something? That is not what happens normally and not with ordinary gases. It takes more energy that mere collisions or normal temperatures would provide to get a gas to split apart.

E: Wrong. Same sort of comment as D. Splitting is not the way these things work. They bounce away as in C.

Five

Half life number 1 would leave 0.5 grams behind.

Half life number 2 would leave 1/2 of 1/2 or 1/4 of the number of grams left.

Answer: 0.25

Answer C

6 0
2 years ago
When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
gizmo_the_mogwai [7]

Answer:

\Delta H=1962.3J

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

\Delta H=mC\Delta T

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

8 0
2 years ago
Why does iron not fit the pattern in column 7
son4ous [18]
Iron doesn't fit because it doesn't have enough atoms or protons in its nucleus so there for it belongs in column 2. <span />
3 0
2 years ago
In each row, check the box under the compound that can reasonably be expected to be more acidic in aqueous solution, e.g. have t
vredina [299]

Answer:

HCH_{3}SO_{2}

H_{3}PO_{3}

HClO_{2}

Explanation:

Every acid (HA) tends to disolve into proton (H^{+}) and anion (A^{-}) in aqueous solution. Acid strength can be determined by measuring this tendency to separate into proton an anion. Strength of an acid can be quantified by its acid dissociation value - Ka. A strong acid will have a tendency to easily release proton and will have larger Ka value and smaller logarithmic value (pKa = - logKa) similar to calculating pH of the solution. So the easiest way to resolve this issue is by looking for Ka or pKa value of the acid (This table may be useful in more complex tasks and is attached below). However, stronger acid can be determined elsehow.

a) Carbon is element 14 with 4 valent electrons and sulfur is element 16 with 6 valence electrons. Thus, sulfur has stronger electronegativity (tendency to attract bonded electrons towards itself). This means that sulfur will hold oxygen tighter to itself so the hydrogen bond to it can be more easily separated from it. HCH_{3}SO_{2} is more acidic in aqueous solution.

b) In H_{3}PO_{4}, phosphorus holds one double bond with oxygen and three OH group equally. To show an acidic tendency, phosphorus would need to let go one hydrogen out of one of OH groups. In H_{3}PO_{3}, phosporus holds two double bong with oxygen, one OH and one hydrogen, all single and lonely, ready to leave phosphorus and show acidic characteristics in aqueous solution. Thus, H_{3}PO_{3} is more acidic compound.

C) In all Cl acids, the electron density is placed around Cl so the more oxygen around Cl, the more acidic will be the chemical. This is comparable to an oxidation state - the bigger oxidation state, the stronger acid will be:

HClO_{4}  ^{+7} >HClO_{3}^{+5} >HClO_{2}^{+3} >HClO_{}^{+1}

HClO_{2} can reasonably be expected to be more acidic in aqueous solution.

4 0
2 years ago
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