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2 years ago

a 0.0250 kg sock spins in a dryer of radius 0.225 m once every 0.304s. how much centripetal force acts on the sock?(unit=N)

Physics

1 answer:

oksano4ka [1.4K]2 years ago

8 0

Answer:

Fc = 1.77N

Explanation:

Lets write down everything we have:

m = 0.0250kg

r = 0.225m

Fc = ? (centripetal force)

T = 0.304s. (period formula is seconds / cycle. 0.304s / 1 cycle, which is equal to 0.304s per cycle. This is the time)

Fc = mv^2 / r

We dont have v, so we can use the formula for constant velocity; v = d/t

v = d/t

distance is 2πr, since that is the circumferance of a circle

v = 2πr / t

v = 2π*0.225 / 0.304

v = 4.65m/s

Now plug everything into Fc formula;

fc=mv^2 / r

Fc = (0.0250kg)(4.65)^2 / 0.304

Fc = 1.77N

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