Question

In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting indentation has a diameter = 3.2 mm. (a) Determine the Brinell hardness number for the metal. (b) If the specimen is steel, estimate the tensile strength of the steel.

Answer 1

Answer:

a) BHN = 181.606

b) UTS = 635.621 MPa

Explanation:

given,

Load = 1500 kg

steel ball of diameter (D) = 10 mm

resulting indentation diameter (d)= 3.2 mm

brinell hardness number

$BHN = \dfrac{2P}{(\pi D)(D - \sqrt{D^2-d^2})}$

$BHN = \dfrac{2\times 1500}{(\pi \times 10)(10 - \sqrt{10^2-3.2^2})}$

$BHN = \dfrac{3000}{16.519}$

BHN = 181.606

b) The tensile strength of the steel

UTS = 3.5 (BHN)

UTS = 3.5  x (181.606)

UTS = 635.621 MPa