Draw a triacylglycerol (triglyceride) made from glycerol, myristic acid [CH3(CH2)12COOH], palmitic acid [CH3(CH2)14COOH], and ol
eic acid [CH3(CH2)7CH=CH(CH2)7COOH(cis)]. Place palmitic acid at the middle position. Cis/trans isometry is graded
1 answer:
Answer:
The triglyceride made from glycerol, myristic acid, palmitic acid and cis-oleic acid is shown in the attached pictures.
Explanation:
A triglyceride or triacylglyceride is an ester derived from glycerol and three fatty acids. The fatty acids of this exercise are myristic acid, palmitic acid and oleic acid.
A fatty acid is a biomolecule of lipid nature formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group.
The myristic acid has a carbon chain of 14 carbon atoms with a carboxyl group at one end.
Palmitic acid has a carbon chain of 16 carbon atoms with a carboxyl group at one end.
Oleic acid has a carbon chain of 18 carbon atoms with a carboxyl group at one end and a double bond at position 9.
Triglyceride is formed by the esterification of the glycerol oxidrile group and the carboxyl acid group.
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Answer:
12.78 kJ
Explanation:
The correct balanced reaction would be
Mass of methanol =
Moles of methanol can be obtained by dividing the mass of methanol with its molar mass
Enthalpy change for the number of moles is given by
The change in enthalpy is 12.78 kJ.