Draw a triacylglycerol (triglyceride) made from glycerol, myristic acid [CH3(CH2)12COOH], palmitic acid [CH3(CH2)14COOH], and ol
eic acid [CH3(CH2)7CH=CH(CH2)7COOH(cis)]. Place palmitic acid at the middle position. Cis/trans isometry is graded
1 answer:
Answer:
The triglyceride made from glycerol, myristic acid, palmitic acid and cis-oleic acid is shown in the attached pictures.
Explanation:
A triglyceride or triacylglyceride is an ester derived from glycerol and three fatty acids. The fatty acids of this exercise are myristic acid, palmitic acid and oleic acid.
A fatty acid is a biomolecule of lipid nature formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group.
The myristic acid has a carbon chain of 14 carbon atoms with a carboxyl group at one end.
Palmitic acid has a carbon chain of 16 carbon atoms with a carboxyl group at one end.
Oleic acid has a carbon chain of 18 carbon atoms with a carboxyl group at one end and a double bond at position 9.
Triglyceride is formed by the esterification of the glycerol oxidrile group and the carboxyl acid group.
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0.17 M is the is the molal concentration of this solution
Explanation:
Data given:
freezing point of glucose solution = -0.325 degree celsius
molal concentration of the solution =?
solution is of glucose=?
atomic mass of glucose = 180.01 grams/mole
freezing point of glucose = 146 degrees
freezing point of water = 0 degrees
Kf of glucose = 1.86 °C
ΔT = (freezing point of solvent) - (freezing point of solution)
ΔT = 0.325 degree celsius
molality =?
ΔT = Kfm
rearranging the equation:
m =
m= 0.17 M
molal concentration of the glucose solution is 0.17 M
Explanation:
It is known that efficiency is denoted by .
The given data is as follows.
= 0.82,
= (21 + 273) K = 294 K
= 200 kPa,
= 1000 kPa
Therefore, calculate the final temperature as follows.
0.82 =
= 1633 K
Final temperature in degree celsius =
=
Now, we will calculate the entropy as follows.
For 1 mole,
It is known that for the value of
= 0.028 kJ/mol.
Therefore, putting the given values into the above formula as follows.
=
= 0.0346 kJ/mol
or, = 34.6 J/mol (as 1 kJ = 1000 J)
Therefore, entropy change of ammonia is 34.6 J/mol.
Answer:
The empirical formula of the solid metal oxide is :
Explanation:
M atom is present in the every corner and in the center of every face.
Number of m atoms :
Number of tetrahedral voids in F.C.C = 2n = 2 × 4 = 8
Oxide ion is present in the half of the tetrahedral void
Number oxide ions =
The molecular formula of the solid metal oxide is :
The empirical formula represent the lowest number of atoms present in a compound.
The empirical formula of the solid metal oxide is :