Answer:
The triglyceride made from glycerol, myristic acid, palmitic acid and cis-oleic acid is shown in the attached pictures.
Explanation:
A triglyceride or triacylglyceride is an ester derived from glycerol and three fatty acids. The fatty acids of this exercise are myristic acid, palmitic acid and oleic acid.
A fatty acid is a biomolecule of lipid nature formed by a long linear hydrocarbon chain, of different length or number of carbon atoms, at the end of which is a carboxyl group.
The myristic acid has a carbon chain of 14 carbon atoms with a carboxyl group at one end.
Palmitic acid has a carbon chain of 16 carbon atoms with a carboxyl group at one end.
Oleic acid has a carbon chain of 18 carbon atoms with a carboxyl group at one end and a double bond at position 9.
Triglyceride is formed by the esterification of the glycerol oxidrile group and the carboxyl acid group.
Answer:
Explanation:
The half-cell reduction potentials are
Ag⁺(aq) + e⁻ ⇌ Ag(s) E° = 0.7996 V
Fe²⁺(aq) + 2e⁻ ⇌ Fe(s) E° = -0.447 V
To create a spontaneous voltaic cell, we reverse the half-reaction with the more negative half-cell potential.
The anode is the electrode at which oxidation occurs.
The equation for the oxidation half-reaction is
Complete Question
The complete question is shown on the first uploaded image
Answer
a
As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure
b
c
The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).
Explanation
In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation
The next thing is to obtain the new pressure of the gas , using boyle's law
Since the this process is isothermal , the change in heat is equal to zero
i.e q = 0 J
The workdone to move the gas to the other container is zero because the the pressure at this second container is zero due to the fact that it is a vacuum
i.e
Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0
This is because the change in internal energy is equal to a summation of change in heat and the workdone
i.e
Generally the change in enthalpy is mathematically represented as
Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for change in enthalpy
