Question

A car is travelling at a steady velocity of 28 m/s. It accelerates for 6 seconds to overtake a van. Its new velocity is 32.5 m/s. Calculate the acceleration of the car.

Answer 1

acceleration= 2.25m/s²

acceleration=final velocity (v) - initial velocity (u)÷ time

that is, a=v-u/t

a=?, v=32.5m/s, u= 28m/s, and t= 6s

a=32.5-28/6

a=4.5/6

a= 2.25m/s²

Answer 2

Answer: The acceleration of the car is $0.75m/s^2$

Explanation:

To calculate the acceleration of the car, we use first equation of motion:

$v=u+at$

where,

v = final velocity of the car = 32.5 m/s

u = initial velocity of the car = 28 m/s

a = acceleration of the car = ?

t = time taken = 6 sec

Putting values in above equation, we get:

$32.5=28+(a\times 6)\\\\a=\frac{32.5-28}{6}\\\\a=0.75m/s^2$

Hence, the acceleration of the car is $0.75m/s^2$