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Setler [38]
2 years ago
3

Center of Mass ProblemPluto and Charon. Pluto’s diameter is approximately 2370 km, and the diameter of itssatellite Charon is 12

50 km. Although the distance varies, they are often about 19,700 kmapart, center to center. Assuming that both Pluto and Charon have the same compositionand hence the same average density, find the location of the center of mass of this systemrelative to the center of Pluto.
Physics
1 answer:
Monica [59]2 years ago
8 0

Answer:

2520.54463 km

Explanation:

The  location  of  the  center  of  mass  is  given  by

r_{cm}=\frac{\sum m_j\vecr}{\sum m_j}

Using Coordinates  with  the  origin  at  the  center  of  Pluto  and  the  +x direction  toward Charon, so

x_p = 0

x_c = 19700 km

m=\frac{4}{3}\pi r^3=\frac{1}{6}\pi d^3 = Mass

d_c = Diameter of Charon

d_p = Diameter of Pluto

\\\Rightarrow x_{cm}=\frac{m_px_p+m_cx_c}{m_p+m_c}\\\Rightarrow x_{cm}=\frac{m_c}{m_p+m_c}x_c=\frac{\frac{1}{6}\rho \pi d_c^3}{\frac{1}{6}\rho \pi d_p^3+\frac{1}{6}\rho \pi d_c^3}\\\Rightarrow x_{cm}=\frac{d_c^3}{d_p^3+d_c^3}x_c\\\Rightarrow x_{cm}=\frac{1250^3}{2370^3+1250^3}19700\\\Rightarrow x_{cm}=2520.54463\ km

The location of the center of mass of this systemrelative to the center of Pluto is 2520.54463 km

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Answer:

Yes we can find the initial velocity of car without finding acceleration.

u = 10 m/s.

Explanation:

Given that

s=20 m

Car takes 4 s to come in rest.

We know that when acceleration is constant then we can apply motion equation

v=u+at        ----------1

s=ut+\dfrac{1}{2}at^2       ------2

From equation 1 and 2

s=ut+\dfrac{1}{2}t^2\left (\dfrac{v-u}{t} \right )

So we can say that

s= \left(\dfrac{v+u}{2}\right)t

Given that the velocity of car at final condition will be zero (v=0)

s= \left(\dfrac{0+u}{2}\right)t

s= \left(\dfrac{u}{2}\right)t

From the above equation we can find the initial velocity of car without finding the acceleration

20= \dfrac{u}{2}\times 4

u = 10 m/s

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2 years ago
Stu wanted to calculate the resistance of a light bulb connected to a 4.0 V battery, with a resulting current of 0.5 A. He used
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James Cameron piloted a submersible craft to the bottom of the Challenger Deep, the deepest point on the ocean's floor, 11,000 m
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Answer:

4.1\cdot 10^8 N

Explanation:

First of all, we need to find the pressure exerted on the sphere, which is given by:

p=p_0 + \rho g h

where

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g=9.8 m/s^2 is the gravitational acceleration

h=11,000 m is the depth

Substituting,

p=1.01\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(11,000 m)=1.08\cdot 10^8 Pa

The radius of the sphere is r = d/2= 1.1 m/2= 0.55 m

So the total area of the sphere is

A=4 \pi r^2 = 4 \pi (0.55 m)^2=3.8 m^2

And so, the inward force exerted on it is

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A certain alarm clock ticks four times each second, with each tick representing half a period. The balance wheel consists of a t
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a. I=2.77x10^{-8} kg*m^2

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b.

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K = \frac{4\pi^2* I}{T^2}=\frac{4\pi^2*2.7702 kg*m^2}{(0.5s)^2}

K=4.37 x10^{-6} N*m

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