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Tanzania [10]
2 years ago
4

g Though wizards might be able to manage without air-bags, Muggles certainly need them! Air-bags can be inflated by the decompos

ition of sodium azide, NaN3. At 25.0◦C and 1.10 atm, what volume of N2(g) is produced by the decomposition of 71.4 g NaN3 under the following chemical reaction: 2NaN3(s) → 2Na(l) + 3N2(g) Express your answer in liters
Chemistry
1 answer:
ValentinkaMS [17]2 years ago
6 0

Answer:

40.293 L

Explanation:

So let's count how much moles of N2 gas we will obtain.

2NaN3(s) → 2Na(l) + 3N2(g)

n(N2)=3/2n(NaN3)=3/2*m(NaN3)/M(NaN3)=3/2*71.4/65.01=1.65 mol

So now we need to use the ideal gas law to count liters.

All numbers must be in Si system

pV=nRT

V=(nRT)/p

V=(1.65*8.314*298)/101457.5=0.040293m3=40.293 L

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Enter the balanced complete ionic equation for k2so4(aq)+cai2(aq)→caso4(s)+ki(aq). express your answer as a chemical equation. i
frozen [14]

The ionic equation is as below

Ca^2+(aq) + SO4^2-(aq) ---> CaSO4(s)

EXPLANATION

K2SO4(aq) +Cai2(aq) ---> CaSO4(s) + Ki (aq)

ionic equation

= 2K^+(aq) + SO4^2-(aq) + Ca^2+(aq) + 2i^-(aq) --->CaSO4(s) + 2K^+(aq) +2 i^-(aq)

cancel the spectator ions that is 2k^+ and 2i^-

The net ionic equation is therefore

= Ca^2+(aq) + SO4^2-(aq) ----> CaSO4(s)

6 0
2 years ago
Read 2 more answers
A 0.1025-g sample of copper metal is dissolved in 35 ml of concentrated hno3 to form cu2 ions and then water is added to make a
GalinKa [24]

Molarity is defined as number of moles of solute in 1 L of solution.

Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.

The balanced reaction will be as follows:

Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O

From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:

n=\frac{m}{M}

molar mass of Cu is 63.55 g/mol thus,

n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol

Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:

M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M

Thus, molarity of Cu^{2+} is 0.008 M.



7 0
2 years ago
50 mL of CH3CH2Br (bromoethane) and 50 mL of water are poured into a separatory funnel. Bromoethane is a water‑insoluble compoun
umka21 [38]

Answer:

See explanation below

Explanation:

In this case, we can explain this in a very basic way.

We know that heavier objects will go always at the bottom when we are carrying two objects, one heavier than the other right?

In the same manner works the density of two liquids. In this case, we have a mix of water and bromoethane. Bromoethane is an organic compound and it's less polar than water which is extremely polar. When we mix these two liquids, we can see that both of them are insoluble, so no matter how much we shake the funnel, the liquids will not mix to form a solution.

Instead of that, both of them will be in the funnel, and they'll be gradually separating into two layers. The bromoethane has a higher density than water, this means that in the bottom layer we will have the bromoethane and in the top layer we will have the water.

In case you are wondering what happens if we added water first and then, the bromoethane?, it will happen the same, it does not matter the order you add the liquid, because density here is a very important factor, so when the water is added no matter which position, it will go to the top layer after the bromoethane is added.

Now when the hexane is added, it will form now three layers, and again, density plays an important factor. The higher density will go to the bottom, and the lowest to the top.

In this case, the order of layer will be:

Top layer: hexane (d = 0.66 g/mL)

Middle layer: water (d = 1 g/mL)

Bottom layer: bromoethane (d = 1.46 g/mL)

Hope this helps

6 0
2 years ago
Enter the numbers 1 to 5 to put in order the steps for lighting a Bunsen burner.
ivanzaharov [21]
The correct steps in lighting a Bunsen burner would be as follows: First, clean the area. Get rid of any flammable substances near the burner. Second, close the air supply Third, turn on the gas supply to the burner. Fourth, use a lighter to light the flame.  Fifth, adjust the flow of air to control the flame.
9 0
2 years ago
Read 2 more answers
Yesinia read that certain perfume ingredients, called esters, would agitate bees. Because perfume formulas are secret, she decid
RUDIKE [14]

Answer:

Hypothesis: IF the perfumes contained Ester "X", THEN the bees would be agitated

Control group: The control group would be the group of bees that did not receive any perfume treatment

Experimental group: Bees that were exposed to the different perfumes

Independent variable: The type of perfumes

Dependent variable: the behavior of the bees

Explanation:

An hypothesis is a testable explanation or suggested solution to a problem that is subject to testing (for proving or disproving) via experimentation. The hypothesis of this experiment will be: IF the perfumes contained Ester "X", THEN the bees would be agitated

The control group of an experiment is the group that does not receive the experimental treatment or the group whose independent variable is not changed. In this case, there is no stated control group but control group of this particular experiment could be the BEES THAT WERE NOT EXPOSED TO ANY PERFUME.

The experimental group, as opposed to the control group, is the group that receives experimental treatment. In this case, it is the group of bees that were exposed to the different types of perfumes.

In an experiment, the variable that is deliberately changed by the experimenter is called the independent variable. The independent variable in this question is the TYPE OF PERFUME given to the bees.

The variable that responds to the changes made to the independent variable is called the dependent variable. The dependent variable, which is the measured variable, is THE BEHAVIOR OF THE BEES.

6 0
2 years ago
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