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BigorU [14]
2 years ago
4

Two identical masses are hung from two different flywheels that are initially stationary. Flywheel B is a uniform disk. Flywheel

A has less mass than flywheel B, and its mass is distributed in a uniform ring that is attached to the rotational axis by spokes of negligible mass.
The identical masses are released and allowed to drop from
the same height to the floor. Which of the following statements is correct?
a) The angular accelerations of the two flywheels are equal.
b) The angular acceleration of flywheel A is greater than flywheel B.
c) The angular acceleration of flywheel A is smaller than flywheel B.
d) The angular momentum of the two flywheels will be the same.
e) The kinetic energy of the two flywheels will be the same.
Physics
1 answer:
Readme [11.4K]2 years ago
7 0

Answer:

Option C

The angular acceleration of flywheel A is smaller than flywheel B.

Explanation:

Flywheel B

T = mgr   where m is mass, g is acceleration due to gravity, r is the radius

0.5 mr^{2}\times a_B​​​​​​=mgr

a_B​​​​​​= \frac {2g}{r} where a_B is angular acceleration of Flywheel B

Flywheel A

mr^{2}\times a_A​​​​​​= mgr

a_A=\frac {g}{r} where a_A is angular acceleration of Flywheel A

so, a_A​​​​​​

Therefore, the angular acceleration of flywheel A is smaller than flywheel B.

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A man runs at a velocity of 4.5 m/s for 15.0 min. When going up an increasingly steep hill, he slows down at a constant rate of
madreJ [45]

The man ran  <u>4252.5 meters.</u>

Why?

To solve the problem, we need to divide the exercise into two movements, the first on while the was running at 4.5 m/s for 15 min, and then, while he was slowing down (going up because of the hill).

First movement: Running at 4.5 m/s for 15 min.

We need convert from minutes to seconds,

1min=60seconds\\\\15min*\frac{60seconds}{1min}=900seconds

Now, calculating the distance covered for the first movement, we have:

x_{1}=0+v_{1}*t_{1}\\\\x_{1}=4.5\frac{m}{s}*900s=4050m

So, we know that the man covered 4050m for the first movement, it will be our initial position for the second movement.

Second movement:  acceleration -0.05m/s^2 (because he's slowing down) for 90 seconds, at 4.5m/s.

x_{2}=x_{1}+v_{1}*t+\frac{1}{2}at^{2}\\\\x_{2}=4050m+4.5m\frac{m}{s}*90seconds-\frac{1}{2}*(0.05\frac{m}{s^{2}})*(90s)^{2}\\\\x_{2}=4050m+405m-(0.5*0.05\frac{m}{s^{2}}*8100s^{2})=4050m+405m-202.5m\\\\x_{2}=4252.5m

Hence, we have that he ran 4252.5 m.

Have a nice day!

4 0
2 years ago
A 10 kg ball moving at 13 m/s strikes a 20 kg ball at rest. after the collision the 10 kg ball is moving with a velocity of 7m/s
Lostsunrise [7]

Answer:

30 (kg)

Explanation:

therefore the mass of the ball is 2 so 30 (kg)

6 0
2 years ago
Read 2 more answers
A starship passes Earth at 80% of the speed of light and sends a drone ship forward at half the speed of light rela- tive to its
alisha [4.7K]

Answer:

Check Explanation

Explanation:

Let the speed of the drone relative to earth be u = ?

Let the speed of the drone relative to the starship be u' = 0.5c

Let the speed of the starship relative to earth be v = 0.8c

In the theory of relativity,

The 3 speeds are related thus

u = (u' + v)/[1 + (u'v/c²)]

u = (0.5c + 0.8c)[1 + ((0.8c × 0.5c)/c²)]

u = 1.3c/[1 + (0.4c²/c²)]

u = 1.3c/1.4 = 0.9286 c = 0.93 c = 93% c

8 0
2 years ago
A device that uses electricity and magnetism to create motion is called a _________motor,magnet,generator . In a reverse process
lawyer [7]
A device that uses electricity and magnetism to create motion is called a "Motor" (which converts electric energy into mechanical energy) & <span>In a reverse process, a device that uses motion and magnetism can be used to create "Electromagnetism".

In short, 1st Blank = Motor
2nd Blank = Electromagnetism 

Hope this helps!</span>
5 0
2 years ago
Read 2 more answers
A professor's office door is 0.89 m wide, 2.0 m high, and 4.0 cm thick; has a mass of 25 kg ; and pivots on frictionless hinges.
taurus [48]
In order to answer this question ... strange as it may seem ...
we only need one of those measurements that you gave us
that describe the door.

The door is hanging on frictionless hinges, and there's a torque
being applied to it that's trying to close it.  All we need to do is apply
an equal torque in the opposite direction, and the door doesn't move.

Obviously, in order for our force to have the most effect, we want
to hold the door at the outer edge, farthest from the hinges.  That
distance from the hinges is the width of the door ... 0.89 m.

We need to come up with 4.9 N-m of torque,
applied against the mechanical door-closer.

Torque is (force) x (distance from the hinge).

                                    4.9 N-m  =  (force) x (0.89 m) 

Divide each side by 0.89m:    Force = (4.9 N-m) / (0.89 m)

                                                             =  5.506 N .
7 0
2 years ago
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