answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pashok25 [27]
2 years ago
8

An object of mass 100 kg is initially at rest on a horizontal frictionless surface. At time t = 0, a horizontal force of 10 N is

applied to the object for 1 s and then removed. Which of the following is true of the object at time t = 2s if it is still on the surface?
(A) It is at the same position it had at t 0, since a force of 10 N is not large enough to move such a massive object.
(B) It is moving with constant nonzero acceleration.
(C) It is moving with decreasing acceleration.
(D) It is moving at a constant speed
(E) It has come to rest some distance away from the position it had att 0.
Physics
1 answer:
satela [25.4K]2 years ago
8 0

Answer:

(D) It is moving at a constant speed

Explanation:

Before t = 1s. Due to the force, albeit small, acting on the object, since there's no static friction stopping the object from moving, this mass object would have a constant acceleration and it's velocity would be increasing.

According to Newton's 1st law, an object will stay at a constant speed if the net force acting on it is 0. After t = 1s, horizontally speaking there's no other force exerting on the mass object. There is no friction force at play here as the surface is frictionless.

Therefore the correct statement is (D) It is moving at a constant speed

You might be interested in
A box is sliding with a speed of 4.50 m/s on a horizontal surface when, at point P, it encounters a rough section. The coefficie
Rudiy27

Answer:

a) xf = 5.1 m

b) u = 0.304

c) x = 10.3 m

Explanation:

we will use the following formula:

u = 0.1 + A*x

Si x = 12.5 m, u = 0.6

Clearing A:

A = 0.5/12.5 = 0.04 m^-1

a) we have to:

W = Ekf - Eki

where Ekf = final kinetic energy

Eki = initial kinetic energy

9.8*(0.1xf + ((0.04*xf^2)/(2))) = (4.5^2)/(2)

Clearing xf, we have:

xf = 5.1 m

b) Replacing values for u:

u = 0.1 + (0.04*5.1) = 0.304

c) Wf = Ekf - Eki

-u*m*x*g = 0 - (m*v^2)/2

Clearing x:

x = v^2/(2*u*g) = (4.5^2)/(2*0.1*9.8) = 10.3 m

4 0
2 years ago
Read 2 more answers
Two disks with the same rotational inertia i are spinning about the same frictionless shaft, with the same angular speed ω, but
valentina_108 [34]

Answer:

3. none of these

Explanation:

The rotational kinetic energy of an object is given by:

K=\frac{1}{2}I \omega^2

where

I is the moment of inertia

\omega is the angular speed

In this problem, we have two objects rotating, so the total rotational kinetic energy will be the sum of the rotational energies of each object.

For disk 1:

K_1 = \frac{1}{2}I (\omega)^2 = \frac{1}{2}I\omega^2

For disk 2:

K_2 = \frac{1}{2}I(-\omega)^2 = \frac{1}{2}I\omega^2

so the total energy is

K=K_1 + K_2 = \frac{1}{2}I\omega^2 + \frac{1}{2}I\omega^2 = I\omega^2

So, none of the options is correct.

5 0
2 years ago
Sea level is currently rising at 3.2 mm/yr, and scientists predict that global warming could cause a rise in sea level of 7 m if
Dovator [93]

Answer:

2188 years

Explanation:

given,                                              

see level rising at the rate = 3.2 mm/yr

height of the sea level to rise = 7 m        

time it will take rise 7 m = ?              

we know,                                      

           1 m = 1000 mm                          

           1 mm = 0.001 m                          

rate of increase of rate = 0.0032 m/year                  

time taken to rise = \dfrac{7}{0.0032}\ years

                             = 2187.5 years                                    

Now, time taken by the sea level to rise 7 m is equal to 2188 years.

7 0
2 years ago
A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
butalik [34]

Answer:

The temperature of the gas is 1197.02 K

Explanation:

From ideal gas law;

PV = nRT

Where;

P is the pressure of the gas

V is the volume of the gas

R is ideal gas constant = 8.314 L.kPa/mol.K

T is the temperature of the gas

n is the number of moles of gas

Volume of the gas in the cylindrical container = πr²h

Given;

r = 6/2 = 3 cm = 0.03 m

h = 11 cm = 0.11 m

V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L

number of moles of oxygen gas = Reacting mass / molar mass

=\frac{0.1}{32} = 0.003125, moles

T = \frac{PV}{nR} = \frac{100X0.311}{0.003125X8.314} =1197.02K

Therefore, the temperature of the gas is 1197.02 K

6 0
2 years ago
D=? V=100mL M=1.5kg=___g
Nana76 [90]
If you go to a website known as 'Wolfram' and type in the question they should be able to answer it.  It's basically a very smart calculator.  I'd add a link but I don't want to seem like I'm advertising, and it's against Brainly rules.
8 0
2 years ago
Other questions:
  • What body process converts physical energy to electrical energy?
    9·1 answer
  • A hydraulic press must be used to press-fit two components together in an assembly process. the system must generate at least 77
    13·1 answer
  • Why did the acorn fall to earth instead of rising up to the moon?
    8·2 answers
  • A heat engine has a thermal efficiency of 45%. how much power does the engine produce when heat is transferred into it at a rate
    11·1 answer
  • A wheel rotates with a constant angular acceleration of  rad/s2. During a certain time interval its angular displacement is  r
    7·1 answer
  • The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint O. Dete
    10·1 answer
  • You are driving along a highway at 35.0 m/s when you hear the siren of a police car approaching you from behind at constant spee
    14·1 answer
  • Spacecraft have been sent to Mars in recent years. Mars is smaller than Earth and has correspondingly weaker surface gravity. On
    7·1 answer
  • A balloon and a mass are attached to a rod that is pivoted at P.
    10·1 answer
  • 1. Order the materials from smallest refractive index to largest refractive index.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!