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Yuri [45]
2 years ago
5

Estimate how long it would take one person to mow a football field using an ordinary home lawn mower. suppose that the mower mov

es with a 1-km/h speed, has a 0.5-m width, and a field is 360 ft long and 160 ft wide. 1 m = 3.281 ft.
Physics
1 answer:
HACTEHA [7]2 years ago
4 0
<span>10.7 hours Since we've been told that we have a speed of 1 km/h and a width of 0.5 meters that means that after 1 hour, we can mow a path 0.5 m wide and 1000 m long for a total area of 1000 m * 0.5 m = 500 m^2/hr. Now let's calculate the area of that football field. 360 ft / 3.281 ft/m * 160 ft / 3.281 ft/m = 5350.692864 m^2 Now let's divide that area by the 500 m^2 calculated earlier to see how many hours it will take. 5350.692864 m^2 / 500 m^2/hr = 10.70138573 hr So it would take about 10.7 hours to mow the football field.</span>
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A 125-g metal block at a temperature of 93.2 °C was immersed in 100. g of water at 18.3 °C. Given the specific heat of the metal
Nataly_w [17]

Answer:

34.17°C

Explanation:

Given:

mass of metal block = 125 g

initial temperature T_i = 93.2°C

We know

Q = m c \Delta T   ..................(1)

Q= Quantity of heat

m = mass of the substance

c = specific heat capacity

c = 4.19 for H₂O in J/g^{\circ}C

\Delta T = change in temperature

Now

The heat lost by metal = The heat gained by the metal

Heat lost by metal = 125\times 0.9\times (93.2-T_f)

Heat gained by the water = 100\times 4.184\times(T_f -18.3)

thus, we have

125\times 0.9\times (93.2-T_f) = 100\times 4.184\times(T_f -18.3)

10485-112.5T_f = 418.4T_f - 7656.72

⇒ T_f = 34.17^oC

Therefore, the final temperature will be = 34.17°C

6 0
2 years ago
A wire with a length of 150 m and a radius of 0.15 mm carries a current with a uniform current density of 2.8 x 10^7A/m^2. The c
Mrac [35]

Answer:

The current is 2.0 A.

(A) is correct option.

Explanation:

Given that,

Length = 150 m

Radius = 0.15 mm

Current densityJ=2.8\times10^{7}\ A/m^2

We need to calculate the current

Using formula of current density

J = \dfrac{I}{A}

I=J\timesA

Where, J = current density

A = area

I = current

Put the value into the formula

I=2.8\times10^{7}\times\pi\times(0.15\times10^{-3})^2

I=1.97=2.0\ A

Hence, The current is 2.0 A.

7 0
2 years ago
A car travels at a constant rate for 25 miles, going due east for one hour. Then it travels at a constant rate another 60 miles
egoroff_w [7]

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6 0
1 year ago
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Nuetrik [128]

Answer:

the expected distance is 4.32 m

Explanation:

given data

half life time = 1.8 × 10^{-8} s

speed = 0.8 c = 0.8 × 3 × 10^{8}

to find out

expected distance over

solution

we know c is speed of light in air is 3 × 10^{8} m/s

we calculate expected distance by given formula that is

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put here all these value

expected distance = half life time × speed

expected distance = 1.8 × 10^{-8} ×  0.8 × 3 × 10^{8}

expected distance = 4.32

so the expected distance is 4.32 m

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