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katrin2010 [14]

1 year ago

12

Daria was swimming in a friend’s pool yesterday, when she saw that a fly had landed in the water about 5 feet away from her. She

began screaming, jumped out of the pool as fast as she could, and refused to get back in for the rest of the day. This is not the first time that her fear of bugs has interfered with a nice afternoon outside, and she has been less and less willing to participate in such activities recently. Daria probably suffers from _________.

1 answer:

jasenka [17]1 year ago

5 0

Answer:

Daria probably suffers from Entomophobia.

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A crow drops a 0.11kg clam onto a rocky beach from a height of 9.8m. What is the kinetic energy of the clam when it is 5.0m abov

svp [43]

Answer:

The kinetic energy of the clam at a height of 5.0 m is 5.19 J and the speed of the clam at that height is 9.71 m/s.

<u>Explanation: </u>

<em>Mechanical energy is constant throughout the travel</em>, we know that <em>mechanical energy is calculated by adding potential energy and kinetic energy</em>. Potential energy = $m \times g \times h$ , Kinetic energy = $\frac{1}{2} \times m \times v^{2}$ and Mechanical energy = $m \times g \times h+\frac{1}{2} \times m \times v^{2}$ Kinetic energy is zero at initial point. Now mechanical energy of clam with m=0.11kg,g=9.81 $\frac{m}{s^{2}}$ ,h=9.8 m is = 0.11×9.81×9.8 = 10.58 J.

Mechanical energy of clam at a height of 5.0 m = $0.11 \times 9.81 \times 5+\frac{1}{2} \times m \times v^{2}$ = $5.39+\frac{1}{2} \times m \times v^{2}$ . We know that mechanical energy is constant hence, <em>mechanical energy of clam at height 9.8 m is equal to mechanical energy at height 5.0 m</em>. This is represented as following

10.58 = $5.39+\frac{1}{2} \times m \times v^{2}$ 10.58 – 5.39 = $\frac{1}{2} \times m \times v^{2}$ 5.19 = $\frac{1}{2} \times m \times v^{2}$ kinetic energy of the clam is 5.19 J.

Now speed of the clam at height 5.0 m is 5.19 = $\frac{1}{2} \times 0.11 \times v^{2} \frac{5.19 \times 2}{0.11}=v^{2}$ 94.36 = $v^{2} \sqrt{94.36}=v \quad v$ = 9.71 m/s. The speed of the clam is 9.71 m/s.

6 0

1 year ago

At a local swimming pool, the diving board is elevated h = 5.5 m above the pool's surface and overhangs the pool edge by L = 2 m

Margaret [11]

Answer:

Part a)

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = 1.06 s$

Part c)

$L = 4.86 m$

Explanation:

Part a)

The height of the diving board is given as

$h = 5.5 m$

now the speed of the diver is given as

$v_0 = 2.7 m/s$

when the diver will jump into the water then his displacement in vertical direction is same as that of height of diving board

So we will have

$y = v_y t + \frac{1}{2}at^2$

$h = 0 + \frac{1}{2}gt^2$

$t = \sqrt{\frac{2h}{g}}$

Part b)

$t = \sqrt{\frac{2h}{g}}$

plug in the values in the above equation

$t = \sqrt{\frac{2(5.5 m)}{9.81}$

$t = 1.06 s$

Part c)

Horizontal distance moved by the diver is given as

$d = v_0 t$

$d = 2.7 \times 1.06$

$d = 2.86 m$

so the distance from the edge of the pool is given as

$L = 2.86 + 2$

$L = 4.86 m$

4 0

1 year ago

An experiment consists of determining the speed of automobiles on a highway by the use of radar equipment. The random variable i

faust18 [17]

The random variable in this experiment is a Continuous random variable.

Option D

<u>Explanation</u>:

The continuous random variable is random variable where the data can take infinite variables. For example random variable is taken for measuring "speed of automobiles" on the highways. The radar instrument depicts time taken by automobile in particular what speed. They are the generalization of discrete random variables not the real numbers as a random data is created. It gives infinite sets of all possible outcomes. It is obvious that outcomes of the instrument depend on some "physical variables" those are not predictable as depends on the situation.

8 0

1 year ago

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A disk is spinning about its center with a constant angular speed at first. Let the turntable spin faster and faster, with const

hoa [83]

Answer:

4 (please see the attached file)

Explanation:

While the angular speed (counterclockwise) remained constant, the angular acceleration was just zero.

So, the only force acting on the bug (parallel to the surface) was the centripetal force, producing a centripetal acceleration directed towards the center of the disk.

When the turntable started to spin faster and faster, this caused a change in the angular speed, represented by the appearance of an angular acceleration α.

This acceleration is related with the tangential acceleration, by this expression:

at = α*r

This acceleration, tangent to the disk (aiming in the same direction of the movement, which is counterclockwise, as showed in the pictures) adds vectorially with the centripetal force, giving a resultant like the one showed in the sketch Nº 4.

7 0

1 year ago

Light hits a clear plastic bottle and a granite rock. Which choice most accurately describes the effect of visible light on the

balu736 [363]

Answer:

#4 is the accurate answer.

8 0

2 years ago

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