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Aleonysh [2.5K]
2 years ago
4

If a 66.0 kg hiker eats one of these bars, how high a mountain must he climb to "work off" the calories, assuming that all the f

ood energy goes only into increasing gravitational potential energy?
Physics
1 answer:
kipiarov [429]2 years ago
5 0

Answer:

adc

Explanation:

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Determine the length of a copper wire that has a resistance of 0.172 ? and cross-sectional area of 7.85 × 10-5 m2. The resistivi
KonstantinChe [14]

Answer:

Length of copper wire, l = 785 meters

Explanation:

Given that,

Resistance of the copper wire, R = 0.172 ohms

Area of cross section, A=7.85\times 10^{-5}\ m^2

Resistivity of copper, \rho=1.72\times 10^{-8}\ \Omega-m

The resistance of a wire is given by :

R=\rho\dfrac{l}{A}

l=\dfrac{RA}{\rho}

l=\dfrac{0.172\ \Omega\times 7.85\times 10^{-5}\ m^2}{1.72\times 10^{-8}\ \Omega-m}

l = 785 meters

So, the length of the copper wire is 785 meters. Hence, this is the required solution.

8 0
2 years ago
if a net horizontal force of 175 N is applied to a bike whos mass is 43 kg what acceleration is produced
Anna [14]

Explanation:

f=175N

m=43kg

a=?

know

f=ma

a=f/m

a=175/43

a=4.06m/s

3 0
2 years ago
The average mass of an automobile in the United States is about 1.440x10^6 g express this mass in kilograms
-BARSIC- [3]
From the problem statement, this is a conversion problem. We are asked to convert from units of grams to units of kilograms. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1000 grams is equal to 1 kilogram. We use this as follows:

<span> 1.440x10^6 g ( 1 kg / 1000 g ) = 1440 kg</span><span>
</span>
8 0
2 years ago
A 14000N car traveling at 25m/s rounds a curve of radius 200m. Find the following: a. The centripetal acceleration of the car.
tamaranim1 [39]

Answer:

Explanation:

Given

Weight of car W=14,000\ N

mass of car m=\frac{14,000}{9.8}=1428.57\ N

velocity of car v=25\ m/s

radius r=200\ m

(a)Centripetal acceleration is given by

a_c=\frac{v^2}{r}

a_c=\frac{25^2}{200}

a_c=3.125\ m

(b)Force that provide centripetal acceleration

F=F_c=\frac{mv^2}{r}

F=\frac{1428.57\times 25^2}{200}

F=4464.285\ N

(c)Friction force between car and tires is given by

=\mu N

where \mu=coefficient of static friction

N=normal reaction

Centripetal force will balance the friction force

F_c=F_r

4464.285=\mu \times 1428.57\times 9.8

\mu =0.318

6 0
2 years ago
Read 2 more answers
An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Anarel [89]
Energy is calculated as power*time, so give the wattage of 1200 W (equivalent to 1200 Joules/second) and time of 30 seconds, multiplying these gives 36000 J or 36 kJ of electrical energy.

If electrical charge or current is needed: Power = voltage * current, so given the power of 1200 watts and voltage of 120 V, current is 1200 W / 120 V = 10 Amperes. Charge is calculated by multiplying 10 A*30 s = 300 C.
3 0
2 years ago
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