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Angelina_Jolie [31]
2 years ago
8

A typical radius for a raindrop is 2.0mm. Modelling the raindrop as a thin double-convex lens with radii of curvature |r| = 2.0m

m, compute the focal length of the lens. Water has an index of refraction of 4/3. Select One of the Following: (a) 0 (b) 1mm (c) 2mm (d) 3mm
Physics
1 answer:
Andru [333]2 years ago
8 0

Answer:

option D

Explanation:

given,

radius of curvature of rain drop = r₁ = 2 mm

radius of curvature of convex lens = r₂ = 2 mm

refractive index of water (n) = 4/3

using lens formula to calculate focal length

     \dfrac{1}{f} = (n-1)(\dfrac{1}{r_1}-\dfrac{1}{r_2})

     \dfrac{1}{f} = (\dfrac{4}{3}-1)(\dfrac{1}{2}-\dfrac{1}{-2})

     \dfrac{1}{f} = (\dfrac{1}{3})(\dfrac{1}{2}+\dfrac{1}{2})

     \dfrac{1}{f} = (\dfrac{1}{3})(1)

                  f = 3 mm

hence, the correct answer is option D

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Using the expression for hook's law,

F = ke.............. Equation 1

F = Force of the athlete, k = force constant of the spring, e = extension/compression of the spring.

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F = 750(0.05)

F = 37.5 N

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Two disks with the same rotational inertia i are spinning about the same frictionless shaft, with the same angular speed ω, but
valentina_108 [34]

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3. none of these

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I is the moment of inertia

\omega is the angular speed

In this problem, we have two objects rotating, so the total rotational kinetic energy will be the sum of the rotational energies of each object.

For disk 1:

K_1 = \frac{1}{2}I (\omega)^2 = \frac{1}{2}I\omega^2

For disk 2:

K_2 = \frac{1}{2}I(-\omega)^2 = \frac{1}{2}I\omega^2

so the total energy is

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A moving sidewalk 95 m in length carries passengers at a speed of 0.53 m/s. One passenger has a normal walking speed of 1.24 m/s
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Answer:

a) t = 1.8 x 10² s

b) t = 54 s

c) t = 49 s

Explanation:

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x = x0 + v * t

where

x = position at time t

x0 = initial position

v = velocity

t = time

In this case, the origin of our reference system is at the begining of the sidewalk.

a) To calculate the time the passenger travels on the sidewalk without wlaking, we can use the equation for the position, using as speed the speed of the sidewalk:

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95 m = 0m + 0. 53 m/s * t

t = 95 m/ 0.53 m/s

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t = 95 m/ 1.77 m/s = 54 s

c) In this case, the passenger is located 95 m from the begining of the sidewalk, then, x0 = 95 m and the final position will be x = 0. She walks in an opposite direction to the movement of the sidewalk, towards the origin of the system of reference ( the begining of the sidewalk). Then, her speed will be negative ( v = 0.53 m/s - 2*(1.24 m/s) = -1.95 m/s. Then:

0 m = 95 m -1.95 m/s * t

t = -95 m / -1.95 m/s = 49 s

3 0
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