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2 years ago

A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the

Physics

1 answer:

maxonik [38]2 years ago

6 0

Answer:

A) 0.33 m/s

Explanation:

The standard form of a transverse wave is given by

y = a cos ( ω t − kx ) , k = 2 π / λ

Amplitude, a = 0.002 m

Wavenumber (k)=47.12 and wavelength ( λ ) = 0.133 m

Time period(T)=0.0385 s and angular frequency ( ω ) = 52 π rad/s

Maximum speed of the string is given by aw

Therefore ; max. speed = 0.002 x 52 π = 0.327 m/s

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Waves hitting at an angle and then bending around features of the coast is known as

Pavel [41]

<span>Waves hitting at an angle and then bending around features of the coast is known as Wave refraction
When waves hitting a specific angle, some part of the waves will be closer to the shallow part of the water and some part will be closer to the deeper part of the water, which makes the wave became somehow bent around the shore.</span>

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2 years ago

Classes are canceled due to snow, so you take advantage of the extra time to conduct some physics experiments. You fasten a larg

horrorfan [7]

Answer:

The value is $t_1 = 9 \ s$

Explanation:

Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows

$v = u + at$

Here u = 0 \ m/s

a = 13.5 $m/s^2$

$v = 0 + 13.5 * 3.10$

=> $v = 41.85 \ m/s$

The is distance it covers at this time is

$s = u * t + \frac{1}{2} a * t^2$

=> $s = + \frac{1}{2} * 13.5 * 3.10^2$

=> $s =64.87$

Now when sled stops its the final velocity is $v_f = 0 m/s$ while the initial velocity will be the velocity after its acceleration i.e $v = 41.85 \ m/s$

$v_f = v + a_1t_1$

Here $a_1 = - 4.65$ , the negative sign shows that it is deceleration

$0 = 41.85 - 4.65 * t_1$

=> $t_1 = 9 \ s$

3 0

2 years ago

Vader's light saber is red, while Obi-Wan's light saber is blue, meaning that Obi-Wan's light saber is emitting _____ compared t

Bingel [31]

I assume it woukd be higher energy light waves. when fire is at its hottest state its blue because its burning off so much.

4 0

2 years ago

Read 2 more answers

A monoatomic ideal gas undergoes an isothermal expansion at 300 K, as the volume increased from 0.010 m^3 to 0.040 m^3. The fina

Natali [406]

Answer:

A) 0.0 kJ

Explanation:

Change in the internal energy of the gas is a state function

which means it will not depends on the process but it will depends on the initial and final state

Also we know that internal energy is a function of temperature only

so here the process is given as isothermal process in which temperature will remain constant always

here we know that

$\Delta U = \frac{3}{2}nR\Delta T$

now for isothermal process since temperature change is zero

so change in internal energy must be ZERO

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2 years ago

Using the formula for kinetic energy of a moving particle k=12mv2, find the kinetic energy ka of particle a and the kinetic ener

Flauer [41]

<span>Answer: KE = (11/2)mĎ‰Â˛rÂ˛, particle B must have mass of 2m, while A has mass m. Then the moment of inertia of the system is I = ÎŁ mdÂ˛ = m*(3r)Â˛ + 2m*rÂ˛ = 11mrÂ˛ and then KE = Â˝IĎ‰Â˛ = Â˝ * 11mrÂ˛ * Ď‰Â˛ = 11mrÂ˛Ď‰Â˛ / 2 So I'll proceed under that assumption. For particle A, translational KEa = Â˝mvÂ˛ but v = Ď‰*d = Ď‰*3r, so KEa = Â˝m(3Ď‰r)Â˛ = (9/2)mĎ‰Â˛rÂ˛ For particld B, translational KEb = Â˝(2m)vÂ˛ but v = Ď‰*r, so KEb = Â˝(2m)Ď‰Â˛rÂ˛ so total translational KE = (9/2 + 2/2)mĎ‰Â˛rÂ˛ = 11mĎ‰Â˛rÂ˛ / 2 which is equal to our rotational KE.</span>

5 0

2 years ago