Write a nuclear equation to describe the spontaneous fission of 95 244 Am to form I-134 and Mo-107. Determine how many neutrons
1 answer:
<u>Answer:</u> 3 neutrons are produced in the above nuclear reaction.
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
The nuclear reaction for the fission of Americium-244 isotope follows:
<u>To calculate Y:</u>
Total mass on reactant side = total mass on product side
Hence, 3 neutrons are produced in the above nuclear reaction.
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Answer : The correct option is, Only Student B
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electron.
Therefore, the total number of valence electrons in = 5 + 3(1) = 8
According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.
The Lewis dot structure of student A is wrong because there is a coordinate bond present between the nitrogen and hydrogen is not covalent.
Thus, the correct Lewis-dot structure of is shown by the student B.
0.17 M is the is the molal concentration of this solution
Explanation:
Data given:
freezing point of glucose solution = -0.325 degree celsius
molal concentration of the solution =?
solution is of glucose=?
atomic mass of glucose = 180.01 grams/mole
freezing point of glucose = 146 degrees
freezing point of water = 0 degrees
Kf of glucose = 1.86 °C
ΔT = (freezing point of solvent) - (freezing point of solution)
ΔT = 0.325 degree celsius
molality =?
ΔT = Kfm
rearranging the equation:
m =
m= 0.17 M
molal concentration of the glucose solution is 0.17 M