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marishachu [46]

2 years ago

9

Kevin dislikes his teacher; therefore, Kevin thinks his teacher dislikes him. Which of the following defense mechanisms best rep

resents this scenario? A. identification B. repression C. displacement D. projection

2 answers:

icang [17]2 years ago

3 0

I believe the answer is D. projection because he has that feeling so he is projecting it back on his teacher believing she feels the same way about him<span />

Helen [10]2 years ago

3 0

Answer: Option (D) is the correct answer.

Explanation:

Since Kevin don't like his teacher, this makes him project an image of his teacher that his teacher also dislikes him.

Therefore, due to his own disliking about his teacher, he has concluded the same from his teacher's side.

Thus, we can conclude that projection is the defense mechanisms best represents this scenario.

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Not too long ago houses were protected from excessive currents by fuses rather than circuit breakers. sometimes a fuse blew out

olganol [36]

Answer: Resistance = $8.21 \times 10^{-8} \Omega$

The approximate diameter of a penny is, <em>d</em> = 20 mm

thickness of penny is, <em>L = </em> 1.5× $10^{-3}$ mm

The area of penny along circular face is, $A = \frac{\pi d^2}{4} =\frac{\pi (20 mm\frac{1 m}{1000 m})^2}{4}$

= 3.14× $10^{-4}$ m²

The resistivity of copper is <em>ρ</em> = 1.72 x 10-8 Ωm.

Resistance,

$R = \rho \frac{L}{A} = (1.72 \times 10^{-8} \Omega m)\frac{1.5 \times 10^{-3} m}{3.14 \times 10^{-4} m^2} = 8.21 \times 10^{-8} \Omega$

5 0

2 years ago

You are playing a game called "Will It Float?" In this game, you are given a large, square can of tuna. If you know the density

Delicious77 [7]

The only information you would need to decide if the can will float is the density of the can, which requires knowing the mass and volume. If the density of the can is less than one, the can will float. if it is greater than one, it will not float, as water's density is one.

6 0

2 years ago

Read 2 more answers

A child blows a leaf straight up in the air from rest. The leaf accelerates at 1.0\,\dfrac{\text m}{\text s^2}1.0 s 2 m1, point,

Neko [114]

Answer:

Time taken by the leaf to displace by 1.0 m distance is

$t = \sqrt2$ seconds

Explanation:

As we know that initial velocity of the leaf is given as

$v_i = 0$

now the acceleration upwards for the leaf is

$a = 1 m/s^2$

The displacement of leaf in upward direction is

d = 1 m

so now we have

$d = v_i t + \frac{1}{2}at^2$

$1 = 0 + \frac{1}{2}(1) t^2$

$t = \sqrt2$ seconds

3 0

2 years ago

Read 2 more answers

A 2 kg stone is tied to a 0.5 m string and swung around a circle at a constant angular velocity of 12 rad/s. the angular momentu

Illusion [34]

Starting from the angular velocity, we can calculate the tangential velocity of the stone:
$v=\omega r= (12 rad/s)(0.5 m)= 6 m/s$

Then we can calculate the angular momentum of the stone about the center of the circle, given by
$L=mvr$
where
m is the stone mass
v its tangential velocity
r is the radius of the circle, that corresponds to the length of the string.

Substituting the data of the problem, we find
$L=(2 kg)(6 m/s)(0.5 m)=6 kg m^2 s^{-1}$

3 0

2 years ago

Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin

Oliga [24]

Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

$\mu_o=4\pi \times 10^{-7}\ T-m/A$

Resistivity, $\rho=1.72\times 10^{-8}\ \Omega-m$

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

$R=\rho \dfrac{l}{A}$

$R=\rho \dfrac{l}{\pi r^2}$

$r=\sqrt{\dfrac{\rho l}{R\pi}}$

$r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}$

r = 0.00199 m

or

$r=1.99\times 10^{-3}\ m=2\times 10^{-3}\ m$

The magnetic field on a current carrying wire is given by :

$B=\dfrac{\mu_o I}{2\pi r}$

$I=\dfrac{2\pi rB}{\mu_o}$

$I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}$

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0

2 years ago