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Over [174]
2 years ago
8

Select all the correct answers.

Chemistry
1 answer:
nevsk [136]2 years ago
3 0

Answer:

The energy gained by the peas is lost by the water;

Energy is transferred from the fire to the pot, then to the water, and then to the peas

Explanation:

According to the fundamental laws of thermodynamics, heat flows from hotter objects to colder ones.

Let's analyze the heat flow in each of the systems we have:

  • A pot of water is heated over a fire. We have a system of water/fire. Since water is heated, it gains heat. This means fire loses heat to water.
  • Frozen peas are added to the hot water. We have a system of peas/water. In this scenario, water is hot. Thus, heat flows from water to peas (heat is lost by water and gained by peas).

Analyzing the answer choices, firstly we notice that the energy gained by the peas is lost by the water, as water is hotter than the peas. Hence, this is true.

Secondly, the peas gain energy, as energy is a synonym to heat. This means the fact that peas lose energy is false.

Thirdly, it's false to claim that energy is transferred from the peas to the water and the pot, as we actually have a reverse process: both pot and water are at a higher temperature and heat flows from them towards the peas at a lower temperature.

Fourthly, it's also false to claim that the water receives energy both from the ire and from the frozen peas: the water only gains energy from the fire that is at a higher temperature, but it loses energy to the frozen peas, as the water is hotter than the peas.

Finally, it's true that energy is transferred from the fire to the pot, then to the water, and then to the peas. This is simply understood knowing that the fire here is at the highest temperature and it directly interacts with the pot which transfers energy to the water. The water is now at a higher temperature relatively to the peas, so it transfers energy to the peas afterwards.

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ElenaW [278]

The volume of sphere can be calculated using the following formula:


V=\frac{4}{3}\pi r^{3}


Here, r is radius of the sphere which is 3.5 cm. Putting the value,


V=\frac{4}{3}\pi r^{3}=\frac{4}{3}(3.14)(3.5cm)^{3}=180 cm^{3}


This is equal to the volume of lead, density of lead is 11.34 g/cm^{3} thus, mass of lead can be calculated as follows:


m=d×V


Putting the values,


m=11.34 g/cm^{3}\times 180 cm^{3}=2041.2 g


Let the mass of ore be 1 g, 68.6% of galena is obtained by mass, thus, mass of galena obtained will be 0.686 g.


Now, 86.6% of lead is obtained from this gram of galena, thus, mass of lead will be:


m=0.686×0.866=0.5940 g


Therefore, 0.5940 g of lead is obtained from 1 g of ore for 100% efficiency, thus, for 92.5% efficiency

m=\frac{92.5}{100}\times 0.5940=0.54945 g

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Thus, 2041.2 g of lead obtain from:


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Therefore, mass of ore required to make lead sphere is 3.715 kg.


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2 years ago
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Sergeeva-Olga [200]
The answer is 3.39 mol.

<span>Avogadro's number is the number of molecules in 1 mol of substance.
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</span>6.02 × 10²³ molecules : 1 mol = 2.04 × 10²⁴ molecules : x
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Hello!

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