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GenaCL600 [577]
2 years ago
4

2 MnO4-(aq) + 10 Br-(aq) + 16 H+(aq) → 2 Mn2+(aq) + 5 Br2(aq) + 8 H2O(l). How many electrons are transferred in the reaction rep

resented by the balanced equation above?
Chemistry
1 answer:
Delvig [45]2 years ago
4 0

Answer : The number of electrons transferred are, 10

Explanation :

Rules for the balanced chemical equation in acidic solution are :

First we have to write into the two half-reactions.

Now balance the main atoms in the reaction.

Now balance the hydrogen and oxygen atoms on both the sides of the reaction.

If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the less number of oxygen are present.

If the hydrogen atoms are not balanced on both the sides then adding hydrogen ion (H^+) at that side where the less number of hydrogen are present.

Now balance the charge.

The given balanced redox reaction is,

2MnO_4^-(aq)+10Br^-{aq)+16H^+(aq)\rightarrow 2Mn^{2+}(aq)+5Br_2(aq)+8H_2O(l)

Step 1: Separate the skeleton equation into two half-reactions.

Oxidation : Br^-\rightarrow Br_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

Step 2: Balance all atoms other than H and O.

Oxidation : 2Br^-\rightarrow Br_2

Reduction : MnO_4^-\rightarrow Mn^{2+}

Step 3: Balance O.

Oxidation : 2Br^-\rightarrow Br_2

Reduction : MnO_4^-\rightarrow Mn^{2+}+4H_2O

Step 4: Balance H.

Oxidation : 2Br^-\rightarrow Br_2

Reduction : MnO_4^-+8H^+\rightarrow Mn^{2+}+4H_2O

Step 5: Balance the charge.

Oxidation : 2Br^-\rightarrow Br_2+2e^-

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O

Step 6: Equalize electrons transferred.

Oxidation : 2Br^-\rightarrow Br_2+2e^-    × 5

Reduction : MnO_4^-+8H^++5e^-\rightarrow Mn^{2+}+4H_2O   × 2

and,

Oxidation : 10Br^-\rightarrow 5Br_2+10e^-

Reduction : 2MnO_4^-+16H^++10e^-\rightarrow 2Mn^{2+}+8H_2O

Step 7: Add the two half-reactions.

2MnO_4^-(aq)+16H^+(aq)+10Br^-(aq)\rightarrow 2Mn^{2+}(aq)+8H_2O(l)+5Br_2(aq)

In this reaction, there are 10 number of electrons transferred.

Hence, the number of electrons transferred are, 10

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