Answer: 0.50 mole K2O
Explanation: To convert the mass of K2O to moles we will need to find the molar mass of K2O.
47.2 g K2O x 1 mole K2O / 94 g K2O
= 0.50 mole K2O
Answer:
0.190 M
Explanation:
Let's consider the neutralization reaction between HCl and NaOH.
HCl + NaOH = NaCl + H2O
11.9 mL of 0.160 M NaOH were used. The reacting moles of NaOH were:
0.0119 L × 0.160 mol/L = 1.90 × 10⁻³ mol
The molar ratio of HCl to NaOH is 1:1. The reacting moles of HCl are 1.90 × 10⁻³ moles.
1.90 × 10⁻³ moles of HCl are in 10.0 mL of solution. The molarity of HCl is:
M = 1.90 × 10⁻³ mol / 10.0 × 10⁻³ L = 0.190 M
Answer:
Explanation:
I don't know how you want the conversion done. I use dimensional analysis.
Jane
12 miles / hour [1.6 km/1 mile][1000 m/1 km][1 hour / 3600 sec]
12 * [1.6 * 3600 / 1000 m/s] = 69.12 m/s
5.33 m/s This answer is a bit shorter than using 5280 feet.
Using 5280 feet
12 miles / hour [5280 ft/1 mile] [1 m/3.281 feet] * [1 hr/3600 sec]
12 * 5280 / (3.281 * 3600)
12 *. 4470
5.36
Jack
330 feet / minute [ 1 meter / 3.281 feet] [1 minute / 60 seconds]
330 * 1/(3.281 * 60)
330 * 1/(196.86)
1.676 m/s
She's going faster than he is, no matter which method is used to do the calculation
Answer:
The anode half reaction is : 
Explanation:
In electrochemical cell, oxidation occurs in anode and reduction occurs in cathode.
In oxidation, electrons are being released by a species. In reduction, electrons are being consumed by a species.
We can split the given cell reaction into two half-cell reaction such as-
Oxidation (anode):
Reduction (cathode): 
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overall: 
So the anode half reaction is :
<span>Based on the crystal field strength, Cl ligand would give the longest d-d transition when complexed with Ti(III). as this is the weak field ligand and would cause minimum splitting of d orbitals.</span>
