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2 years ago

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A solid conducting sphere is placed in an external uniform electric field. With regard to the electric field on the sphere's int

erior, which statement is correct?
A.)There is no electric field on the interior of the conducting sphere.
B.)The interior field points in a direction parallel to the exterior field.
C.)The interior field points in a direction opposite to the exterior field.
D.)The interior field points in a direction perpendicular to the exterior field.

1 answer:

Fittoniya [83]2 years ago

3 0

Answer:

The answer is A. There is no electric field on the interior of the conducting sphere.

Explanation:

A solid conducting sphere in a uniform electric field will exert force on the charges in the sphere to redistribute themselves in such a way that both the charges and the field inside the sphere would vanish.

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A box with a mass of 100.0 kg slides down a ramp with a 50 degree angle. What is the weight of the box? N What is the value of t

nadya68 [22]

1) weight of the box: 980 N

The weight of the box is given by:

$W=mg$

where m=100.0 kg is the mass of the box, and $g=9.8 m/s^2$ is the acceleration due to gravity. Substituting in the formula, we find

$W=(100.0 kg)(9.8 m/s^2)=980 N$

2) Normal force: 630 N

The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by

$N=W cos \theta$

where W is the weight of the box, calculated in the previous step, and $\theta=50^{\circ}$ is the angle of the ramp. Substituting, we find

$N=(980 N)(cos 50^{\circ})=630 N$

3) Acceleration: $7.5 m/s^2$

The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by

$a_p = g sin \theta$

Substituting, we find

$W_p = (9.8 m/s^2)(sin 50^{\circ})=7.5 m/s^2$

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2 years ago

A cylindrical rod of steel (E = 207 GPa, 30 × 10 6 psi) having a yield strength of 310 MPa (45,000 psi) is to be subjected to a

Yanka [14]

Answer:

Diameter of the cylinder will be $d=2.998\times 10^4m$

Explanation:

We have given young's modulus of steel $E=207GPa=207\times 10^9Pa$

Change in length $\Delta l=0.38mm$

Length of rod $l=500mm$

Load F = 11100 KN

Strain is given by $strain=\frac{\Delta l}{l}=\frac{0.38}{500}=7.6\times 10^{-4}$

We know that young's modulus $E=\frac{stress}{strain}$

So $207\times 10^9=\frac{stress}{7.6\times 10^{-4}}$

$stress=1573.2\times 10^{-5}N/m^2$

We know that stress $=\frac{force}{artea }$

So $1573.2\times 10^{-5}=\frac{11100\times 1000}{area}$

$area=7.055\times 10^{8}m^2$

So $\frac{\pi }{4}d^2=7.055\times 10^{8}$

$d=2.998\times 10^4m$

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Some fuel cells are powered by hydrogen. Scientists are looking into the decomposition of water (H2O) to make hydrogen fuel with

mr_godi [17]

A challenge scientists face with this process is the use of ultrathin iron oxide, to pull protons off water and produce hydrogen gas, which itself is a poor electrical conductor.

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Walt ran 5 kilometers in 25 minutes, going eastward. What was his average velocity?

storchak [24]

1km per 5 mins
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Two particles collide and stick together. If no external forces act on the two particles, which of the following is correct for

Semmy [17]

Answer:

c. $\Delta p$ =0 and $\Delta k$

Explanation:

We are given that two particles collide and stick together.

If there is no external force act on the two particles then ,it is inelastic collision.

Inelastic collision: There is some loss of kinetic energy but the momentum is conserved.

According to law of conservation of momentum

Initial momentum=Final momentum

Change in momentum=Final momentum-Initial momentum=0

Change in momentum= $\Delta p=0$

Initial kinetic energy is greater than final kinetic energy.

Change in kinetic energy=Final kinetic energy-kinetic energy=- negative

$\Delta k$

Hence, option c is true.

c. $\Delta p$ =0 and $\Delta k$

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2 years ago