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Temka [501]
2 years ago
14

When a comet enters the inner solar system, what part of the comet always points most directly away from the Sun

Physics
2 answers:
d1i1m1o1n [39]2 years ago
8 0

Answer:

Comet Tail

Explanation:

A comet tail— and coma — are characteristics that are evident in comets when the Sun illuminates them and can become apparent from Earth when a comet travels through the inner part of the Solar System.

While a comet enters the inner part of  solar system, sunlight causes the toxic materials inside the comet to vaporize and float out of the center, sweeping away particles with them.

Two, distinct tails are created from dust and gases, being visible by different occurrences; the dust simply reflects sunlight, and the gasses shine through ionization.

Snowcat [4.5K]2 years ago
5 0

Answer:

ionic Coma tail

Explanation:

The Coma of the comet points most directly away from the sun. Coma is the tail formed by the vapor of the ice mass of the comet when comet approaches close to the sun while revolving around it.

This vapor gets ionized on getting closer to the sun and form a halo like structure around the comet other than the vapor tail.

These tails always point away from the Sun as the comet travels around it under the influence of the solar winds.

The vapor and dust tail is least affected by the solar flare since they are larger than the ions of hydrogen.

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If R is the total resistance of three resistors, connected in parallel, with resistances R1, R2, R3, then 1 R = 1 R1 + 1 R2 + 1
ANTONII [103]

Answer:

\Delta R_{max} = 0.46 ohm

Explanation:

Resistance is given of different values

now we have

R_1 = 64 ohm

R_2 = 20 ohm

R_3 = 8 ohm

possible error in all resistance is 0.5 %

now we know that

\Delta R_1 = 0.005\times 64 = 0.32 ohm

\Delta R_2 = 0.005 \times 20 = 0.1 ohm

\Delta R_2 = 0.005 \times 8 = 0.04 ohm

Now the maximum possible error when all resistance is connected in series

\Delta R_{max} = \Delta R_1 + \Delta R_2 + \Delta R_3

\Delta R_{max} = 0.32 + 0.1 + 0.04

\Delta R_{max} = 0.46 ohm

7 0
2 years ago
Alculate the potential difference if 20J of energy are transferred by 8C of charge.
sveta [45]

Answer:

V = 2.5 J/C

Explanation:

<u><em>Given:</em></u>

Energy = E = 20 J

Charge = Q = 8 C

<u><em>Required:</em></u>

Potential Difference = V = ?

<u><em>Formula:</em></u>

V = \frac{E}{Q}

<u><em>Solution:</em></u>

V = 20/8

V = 2.5 J/C

6 0
2 years ago
Sebanyak 0,2 mol gas ideal berada dalam wadah yang volumenya 10 liter dan tekanan 1 atm . berapakah suhu gas tersebut
tamaranim1 [39]

The temperature of the gas is about 600 K

\texttt{ }

<h3>Further explanation</h3>

The Ideal Gas Law that needs to be recalled is:

\large {\boxed {PV = nRT} }

<em>P = Pressure (Pa)</em>

<em>V = Volume (m³)</em>

<em>n = number of moles (moles)</em>

<em>R = Gas Constant (8.314 J/mol K)</em>

<em>T = Absolute Temperature (K)</em>

Let us now tackle the problem !

\texttt{ }

<u><em>Question (Translation):</em></u>

<em>A total of 0.2 moles of ideal gas are in containers with volume of 10 liters and a pressure of 1 atm. What is the temperature of the gas?</em>

<u>Given:</u>

number of moles = n = 0.2 moles

volume of gas = V = 10 liters

pressure of gas = P = 1 atm

gas contant = R = 0.0821 L.atm/mol.K

<u>Unknown:</u>

temperature of gas = T = ?

<u>Solution:</u>

PV = nRT

1 \times 10 = 0.2 \times 0.0821 \times T

10 = 0.01642 \times T

T = 10 \div 0.01642

T \approx 600 \texttt{ K}

\texttt{ }

<h3>Learn more</h3>
  • Minimum Coefficient of Static Friction : brainly.com/question/5884009
  • The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
  • Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

\texttt{ }

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure

8 0
2 years ago
A 2-column table with 4 rows. The first column titled mineral has entries diamond, cubic zirconia, common glass, ruby. The secon
fiasKO [112]

Explanation:

1. diamond

2.common glass

3. cubic zirconia

7 0
2 years ago
Read 2 more answers
Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105
Dovator [93]
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating). 
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
3 0
2 years ago
Read 2 more answers
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