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2 years ago

When a comet enters the inner solar system, what part of the comet always points most directly away from the Sun

Physics

2 answers:

d1i1m1o1n [39]2 years ago

8 0

Answer:

Comet Tail

Explanation:

A comet tail— and coma — are characteristics that are evident in comets when the Sun illuminates them and can become apparent from Earth when a comet travels through the inner part of the Solar System.

While a comet enters the inner part of solar system, sunlight causes the toxic materials inside the comet to vaporize and float out of the center, sweeping away particles with them.

Two, distinct tails are created from dust and gases, being visible by different occurrences; the dust simply reflects sunlight, and the gasses shine through ionization.

Snowcat [4.5K]2 years ago

5 0

Answer:

ionic Coma tail

Explanation:

The Coma of the comet points most directly away from the sun. Coma is the tail formed by the vapor of the ice mass of the comet when comet approaches close to the sun while revolving around it.

This vapor gets ionized on getting closer to the sun and form a halo like structure around the comet other than the vapor tail.

These tails always point away from the Sun as the comet travels around it under the influence of the solar winds.

The vapor and dust tail is least affected by the solar flare since they are larger than the ions of hydrogen.

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The image shows positions of the earth and the moon in which region would an astronaut feel the lightest

trapecia [35]

Answer:

The moon region

Explanation:

This is because there is little to no gravity on the moon. That is where the astronaut would feel the lightest.

5 0

2 years ago

Read 2 more answers

You are testing a new amusement park roller coaster with an empty car with a mass of 130 kg. One part of the track is a vertical

vlada-n [284]

Answer:

Work done by friction along the motion is given as

$W_f = -5857.8 J$

Explanation:

As per work energy theorem we can say

Work done by all forces = change in kinetic energy of the system

so here car is moving from bottom to top

so here the change in kinetic energy is total work done on the car

so here we will have

$W_f + W_g = \frac{1}{2}m(v_f^2 - v_i^2)$

$W_f - mgH = \frac{1}{2}m(v_f^2 - v_i^2)$

now plug in all data in it

$W_f - (130)(9.81)(2\times 12) = \frac{1}{2}(130)(8^2 - 25^2)$

$W_f = 30607.2 - 36465$

$W_f = -5857.8 J$

6 0

2 years ago

What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t

Helen [10]

Missing details: figure of the problem is attached.

We can solve the exercise by using Poiseuille's law. It says that, for a fluid in laminar flow inside a closed pipe,

$\Delta P = \frac{8 \mu L Q}{\pi r^4}$

where:

$\Delta P$ is the pressure difference between the two ends

$\mu$ is viscosity of the fluid

L is the length of the pipe

$Q=Av$ is the volumetric flow rate, with $A=\pi r^2$ being the section of the tube and $v$ the velocity of the fluid

r is the radius of the pipe.

We can apply this law to the needle, and then calculating the pressure difference between point P and the end of the needle. For our problem, we have:

$\mu=0.001 Pa/s$ is the dynamic water viscosity at $20^{\circ}$

L=4.0 cm=0.04 m

$Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s$

and r=1 mm=0.001 m

Using these data in the formula, we get:

$\Delta P = 3200 Pa$

However, this is the pressure difference between point P and the end of the needle. But the end of the needle is at atmosphere pressure, and therefore the gauge pressure (which has zero-reference against atmosphere pressure) at point P is exactly 3200 Pa.

8 0

2 years ago

The equation for the change in the position of a train (measured in units of length) is given by the following expression: x = ½

mel-nik [20]

Answer:

(B) (length)/(time³)

Explanation

The equation x = ½ at² + bt³ has to be dimensionally correct. In other words the term bt³ and ½ at² must have units of change of position = length.

We solve in order to find the dimension of b:

[x]=[b]*[t]³

length=[b]*time³

[b]=length/time³

6 0

2 years ago

Read 2 more answers

As a youngster, you drive a nail in the trunk of a young tree that is 3 meters tall. The nail is about 1.5 meters from the groun

Lera25 [3.4K]

Answer:

15m

Explanation:

Hello! first to solve this problem we must find that so much that the tree grew in the 15 years this is achieved by dividing the height of the tree before and after

$\frac{30m}{3m} =10 times$

the tree grew 10 times its initial length in 15 years, so to find how tall the nail is, we multiply this factor by 1.5m

X=(1.5m)(10)=15m

the nail is 15 meters above ground level

8 0

2 years ago