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Sidana [21]
2 years ago
9

Antacids are taken to counterbalance excess hydrochloric acid, HCl, in the stomach. Complete and balance the following neutraliz

ation reactions involving various antacid tablets. If there should be only one mole of the product or reagent in the reaction, then leave the option blank. (A blank answer corresponds to 1 and coefficients of 1 are not expressly written in chemical formulas.)
2, 3, CaCl2, CaCl, MgCl2, 4, MgCl (<-------The options to choose from)
______CaCO3+______HCl -----> _______ /_______+_______H2O+_______CO2
Mg(OH)2+ ______HCl------>________ /________+________H2O
Balance each element on each side of the reaction arrow by adding coefficients to the reactants and products.
The antacid Brioschi, which has been used to relieve heartburn, is mainly sodium bicarbonate. Predict the products, then write the balanced neutralization reaction for the antacid Brioschi in the stomach where the main acid present is hydrochloric acid, HCl.
Express your answer as a chemical equation.
Chemistry
1 answer:
abruzzese [7]2 years ago
7 0

Answer:

1. CaCO3 + 2HCl —> CaCl2 + H2O + CO2

2. Mg(OH)2 + 2HCl —> MgCl2 + 2H2O

3. Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

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How are exothermic and endothermic reactions linked in the process of refining metal ore?
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The intended sense is that of a reaction that depends on absorbing heat if it is to proceed. The opposite of an endothermic process is an exothermic process, one that releases "gives out" energy in the form of heat
6 0
2 years ago
A mixture of three gases has a pressure at 298 K of 1380 mm Hg. The mixture is analysed and is found to contain 1.27 mol CO2, 3.
enot [183]

Answer:

The partial pressure of Ar is 356.04 mm Hg (= 0.4685 atm)

Explanation:

<u>Step 1:</u> Data given

A mixture of three gases has a total pressure of 1380 mm Hg (=1.81579 atm) at 298 K

Moles of CO2 = 1.27 moles

Moles of CO = 3.04 moles

Moles of Ar = 1.50 moles

<u>Step 2:</u> Calculate total number of moles

Total number of moles = n(CO2)+ n(CO)+ n(Ar) = 1.27 mol+ 3.04 mol+ 1.50 mol = 5.81 moles

<u>Step 3:</u> Calculate mol fraction Ar

Mol fraction Ar = 1.50 mol/5.81 mol = 0.258

<u>Step 4</u>: Calculate partial pressure

1380 mm Hg * 0.258 moles Ar = 356.04 mm Hg = 0.4685 atm

The partial pressure of Ar is 356.04 mm Hg (= 0.4685 atm)

8 0
2 years ago
In an ionic bond:
inna [77]
Correct answer is 
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8 0
2 years ago
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A 103.8g sample of nitric acid solution that is 70.0% HNO3 contains by mass
soldi70 [24.7K]
w/w percentage <span>
               = mass of the pure compound / total mass of the sample x 100%

70% HNO₃ contains by mass means every 100 g of sample has 70 g of HNO₃.</span><span>

The mass of solution = 103.8 g
Hence the mass of HNO₃ = 103.8 g x 70%</span><span>
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3 0
2 years ago
What is the freezing point of a 1.40 m aqueous solution of a nonvolatile un-ionized solute? (the freezing point depression const
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Depression is freezing point is a colligative property. It is mathematically expressed as ΔTf = Kf X m

where Kf = <span>freezing point depression constant = 1.86°c kg /mol (for water)
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</span>∴ ΔTf = Kf X m  = 1.86 X 1.40 = 2.604 oC

Now, for water freezing point = 0 oC

∴Freezing point of solution = -2.604 oC
6 0
2 years ago
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