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Sidana [21]
1 year ago
9

Antacids are taken to counterbalance excess hydrochloric acid, HCl, in the stomach. Complete and balance the following neutraliz

ation reactions involving various antacid tablets. If there should be only one mole of the product or reagent in the reaction, then leave the option blank. (A blank answer corresponds to 1 and coefficients of 1 are not expressly written in chemical formulas.)
2, 3, CaCl2, CaCl, MgCl2, 4, MgCl (<-------The options to choose from)
______CaCO3+______HCl -----> _______ /_______+_______H2O+_______CO2
Mg(OH)2+ ______HCl------>________ /________+________H2O
Balance each element on each side of the reaction arrow by adding coefficients to the reactants and products.
The antacid Brioschi, which has been used to relieve heartburn, is mainly sodium bicarbonate. Predict the products, then write the balanced neutralization reaction for the antacid Brioschi in the stomach where the main acid present is hydrochloric acid, HCl.
Express your answer as a chemical equation.
Chemistry
1 answer:
abruzzese [7]1 year ago
7 0

Answer:

1. CaCO3 + 2HCl —> CaCl2 + H2O + CO2

2. Mg(OH)2 + 2HCl —> MgCl2 + 2H2O

3. Na2CO3 + 2HCl —> 2NaCl + H2O + CO2

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Express 601 kg as an integer
BigorU [14]
601 expressed as an integer is 3.
An integer refers to a whole number, a number which do not contain any decimal point. 
To express any given number as an integer, just count the number of significant figures in the number and write this down as a whole number.
3 0
2 years ago
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How many grams are contained in a 0.893 mol sample of methane, ch4?
irina [24]

We are given with a compound, Methane (CH4), with a molar mass of 0.893 mol sample. We are tasked to solve for it's corresponding mass in g. We need to solve first the molecular weight of Methane, that is

C=12 g/mol

H=1g/mol

 

CH4= 12 g/mol +1(4) g/mol = 16 g/mol

With 0.893 mol sample, its corresponding mass is

g CH4= 0.893 mol x 16g/mol =14.288 g

Therefore, the mass of methane is 14.288 g

6 0
1 year ago
The beaker shown below contains a 0.58 M solution of dye in water. How many moles of dye are there in the beaker?
seropon [69]
According to the equation of molarity:

Molarity= no.of moles / volume per liter of Solution

when we have the molarity=0.58 M and the beaker at 150mL so V (per liter) = 150mL/1000 = 0.150 L

by substitution:
∴ No.of moles = Molarity * Volume of solution (per liter)
                        = 0.58 * 0.150 = 0.087 Moles
7 0
1 year ago
Read 2 more answers
List the bonding pairs H and I; S and O; K and Br; Si and Cl, H and F; Se and S; C and H in order of increasing covalent charact
stellarik [79]

Answer:

1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br)

Explanation:

The covalent character always increases down the group, this is because ionic character decreases down the group and also electronegativity.

In the same way, Covalent character always decreases across a period because electronegativity increases across a period.

The higher the electronegativity values between the two atoms, the more ionic it will be.

5 0
2 years ago
A patient is having an allergic reaction and takes a 12.5mg tablet of the over‑the‑counter antihistamine diphenhydramine hydroch
horsena [70]

12.5 mg of the tablet contains 2.58×10¹⁹ molecules of diphenhydramine hydrochloride, C₁₇H₂₂ClNO

From Avogadro's hypothesis,

<h3>1 mole of any substance = 6.02×10²³ molecules </h3>

Therefore,

1 mole of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Next, we shall determine the mass (in mg) of 1 mole of C₁₇H₂₂ClNO. This can be obtained as follow:

1 mole of C₁₇H₂₂ClNO = (17×12) + (22×1) + 35.5 + 14 + 16

= 204 + 22 + 35.5 + 14 + 16

= 291.5 g

Multiply by 1000 to express in mg

291.5 × 1000 = 291500 mg

Thus,

<h3>1 mole of C₁₇H₂₂ClNO = 291500 mg</h3>

Therefore,

291500 mg of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Finally, we shall determine the number molecules in 12.5 mg of C₁₇H₂₂ClNO. This can be obtained as follow:

291500 mg of C₁₇H₂₂ClNO = 6.02×10²³ molecules

Therefore

12.5 mg of C₁₇H₂₂ClNO = \frac{12.5 * 6.02*10^{23}}{291500}\\

<h3>12.5 mg of C₁₇H₂₂ClNO = 2.58×10¹⁹ molecules </h3>

Therefore, we can conclude that 12.5 mg of the tablet contains 2.58×10¹⁹ molecules of diphenhydramine hydrochloride, C₁₇H₂₂ClNO

Learn more: brainly.com/question/24717429

7 0
1 year ago
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