Answer:
293.7 degrees
Explanation:
A = - 8 sin (37) i + 8 cos (37) j
A + B = -12 j
B = a i+ b j , where and a and b are constants to be found
A + B = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j
- 12 j = (a - 8 sin (37) ) i + ( 8cos(37) + b ) j
Comparing coefficients of i and j:
a = 8 sin (37) = 4.81452 m
b = -12 - 8cos(37) = -18.38908
Hence,
B = 4.81452 i - 18.38908 j ..... 4 th quadrant
Hence,
cos ( Q ) = 4.81452 / 12
Q = 66.346 degrees
360 - Q = 293.65 degrees from + x-axis in CCW direction
Newton's first law says that an object at rest tends to stay at rest while an object in motion stays in motion at a constant velocity unless acted upon by an outside force so the amount of force behind the defensive football player (N) was greater than the quarterback's so he was able to over power him which is also called unbalanced forces
Answer:

Explanation:
From Newton's second law,

where
is the force,
is the mass and
is the acceleration.
From Hooke's law,

where
is the spring constant and
is the displacement function measured from the origin. The negative sign indicates the force acts in opposite direction to the displacement. In fact, it is a restoring force; it acts to return the spring to its original undisturbed position.
Since both forces are the same,


The implication of this is that the acceleration is proportional to the displacement but opposite to it. That last statement is the definition of a simple harmonic motion which this is.
The ratio
is a constant except in situations where the mass is varying (say, the mass on the spring is a decaying material).
Using the a=vf-vi divided by tf-ti:
A is acceleration
Vf is final velocity- 330
Vi is intial velocity-30
Tf is final time-15
Ti is initial time-0
A = 330-30 divided by 15-0
A = 300 divided by 15
A= 20 m/s^2
Hope this helps
<span>Answer:
For a disc, the moment of inertia about the perpendicular axis through the center is given by 0.5MR^2.
where M is the mass of the disc and R is the radius of the disc.
For the axis through the edge, use parallel axis theorem.
I = I(axis through center of mass) + M(distance between the axes)^2
= 0.5MR^2 + MR^2 (since the axis through center of mass is the axis through the center)
= 1.5 MR^2</span>