Question

A gas had an initial pressure of 4.80atm in a 5.50L container. After transfering it to a 9.60L container, the gas was found to have a pressure of 2.10atm and a temperature of 25.00∘C. What was the initial temperature in degrees Celsius?

Answer 1

To solve this problem we will apply the concepts related to the ideal gas equations. Which defines us that the relationship between pressure, temperature and volume in the first state must be equivalent in the second state of matter. In mathematical terms this is

$\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$

If we rearrange the equation to find the Temperature at state 1 we have that

$T_1 = \frac{P_1V_1T_2}{P_2V_2}$

Replacing our values we have that

$T_1 = \frac{(4.8*5.5*298.15)}{(2.1*9.6)}$

$T_1 = 390.435K$

Therefore the temperature is 390.435K