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taurus [48]
2 years ago
14

What is the mass of a cylinder of lead that is 1.80 in in diameter, and 4.12 in long. The density of lead is 11.4 g/mL.

Chemistry
1 answer:
Rzqust [24]2 years ago
3 0

Answer:

124.26g

Explanation:

Diameter  = 1.80 , length (h) = 4.12 , density = 11.4

Density = mass / volume

Volume = area x height

Area = #d2 ➗ 4

Where #(pi) = 3.142

Area = 3.142 x 1.80 square ➗ 4

Area = 10.2/4 = 2.6

Volume = area x height

Volume = 2.6 x 4.2=10.9

Density = mass / vol

Mass = density x vol

Mass = 11.4 x 10.9

Mass 124.26g

I hope this was helpful, Please mark as brainliest

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The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.

Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).

Nomenclature:

                       In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.

Name of Formate:

                             Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.

E.g.

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                H₃CCOOH (acetic acid)     →      H₃CCOO⁻ (acetate)  +  H⁺

Formal Charges:

                           Formal charges are calculated using following formula,

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For Oxygen:

                    F.C  =  [6] - [6 + 2/2]

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                    F.C  =  -1

For Sodium:

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                    F.C  =  [1] - [0]

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Explanation:

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According to stoichiometry:

3 moles of N_2 is produced by 2 moles of N_2H_4

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Explanation: solution attached:

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What is the pH of a solution made by mixing 15.00 mL of 0.100 M HCl with 50.00 mL of 0.100 M KOH? Assume that the volumes of the
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Answer:

The correct answer is: pH = 12.73

Explanation:

The <em>neutralization reaction</em> between HCl and KOH is given by the following chemical equation:

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Since HCl is a strong acid and KOH is a strong base, HCl is completely dissociated into H⁺ and Cl⁻ ions, whereas KOH is dissociated completely into K⁺ and OH⁻ ions.

For acids, the number of equivalents is given by the moles of H⁺ ions (in this case: 1 equivalent per mol of HCl). For bases, the number of equivalents is given by the moles of OH⁻ ions (in this case: 1 equivalent per mol of KOH).

The H⁺ ions from HCl will react with OH⁻ ions of KOH to give H₂O. The pH is calculated from the difference between the equivalents of H⁺ and OH⁻:

equivalents of H⁺= volume HCl x Molarity HCl

                            = (15.0 mL x 1 L/1000 mL) x 0.100 mol/L

                            = 1.5 x 10⁻³ eq H⁺

equivalents of OH⁻= volume KOH x Molarity KOH

                               = (50.0 mL x 1 L/1000 mL) X 0.100 mol/L

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So, the concentration of OH⁻ ions in the solution is given by:

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From  [OH⁻], we can calculate pOH:

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