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horrorfan [7]
2 years ago
13

Due to the evaporation of the jogger's sweat, the change in entropy of the universe is:

Physics
1 answer:
JulijaS [17]2 years ago
7 0

Answer:

a

Explanation:

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A stationary boat in the ocean is experiencing waves from a storm. The waves move at 59 km/h and have a wavelength of 145 m . Th
krek1111 [17]

Answer:

The time elapses until the boat is first at the trough of a wave is 4.46 seconds.

Explanation:

Speed of the wave, v = 59 km/h = 16.38 m/s

Wavelength of the wave, \lambda=145\ m

If f is the frequency of the wave. The frequency of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{16.38\ m/s}{145\ m}\\\\f=0.112\ Hz

The time period of the wave is given by :

T=\dfrac{1}{f}\\\\T=\dfrac{1}{0.112\ Hz}\\\\T=8.92\ s

We need to find the time elapses until the boat is first at the trough of a wave. So, the time will be half of the time period of the wave.

T=\dfrac{8.92}{2}\\\\T=4.46\ s

Hence, this is the required solution.

5 0
2 years ago
The frequency of a wave increases. If the speed of the wave remains constant, what happens to the distance between successive cr
Zepler [3.9K]

Answer:

The distance between successive crests decreases.

Explanation:

If f is the frequency and \lambda is the wavelength of a wave, then the speed of the wave is given by :

v=f\times \lambda

on rearranging,

f=\dfrac{v}{\lambda}

We know that wavelength of a wave is equal to the distance between successive crests or troughs.

If the frequency of a wave increases while its speed remains constant, the wavelength decreases i.e. the distance between successive crests decreases.

8 0
2 years ago
A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a
grigory [225]
<h2>Answer:</h2>

(c) 5m/s²

<h2>Explanation:</h2>

Total acceleration (a) of a particle in a circular motion is the vector sum of the radial or centripetal acceleration (a_{C}) of the particle and the tangential acceleration (a_{T}) of the particle and its magnitude can be calculated as follows;

a = \sqrt{(a_{C})^2 + (a_{T})^2}           ---------------------(i)

<em>But;</em>

a_{C} = \frac{v^{2} }{r}      ------------------------------(ii)

Where;

v = instantaneous velocity

r =  radius of the circular path of motion

<em>From the question;</em>

v = 30m/s

r = 300m

(i) First let's calculate the centripetal acceleration by substituting the values above into equation (ii) as follows;

a_{C} = \frac{30^{2} }{300}

a_{C} = \frac{900}{300}

a_{C} = 3m/s²

(ii) From the question, the velocity of the particle is increasing at a constant rate of 4m/s²  and that is the tangential acceleration a_{T}, of the particle. i.e;

a_{T} = 4m/s²

(iii) Now substitute the values of a_{C} and a_{T} into equation (i) as follows;

a = \sqrt{(3)^2 + (4)^2}

a = \sqrt{(9) + (16)}

a = \sqrt{25}

a = 5m/s²

Therefore, the magnitude of its total acceleration a, is 5m/s²

5 0
2 years ago
The furnace keeps houseAat 25◦C, while thefurnace in houseBkeeps it at 20◦C. Which house requires heat to be supplied by its fur
EleoNora [17]

Answer:

House A requires heat at a slightest faster rate than B

Explanation:

House A requires heat at a slightest faster rate than B due to the slight high temperature the furnace A is.

5 0
2 years ago
An astronaut hits a golf ball of mass m on the Moon, where there is no atmosphere and the acceleration due to gravity is g 6 , w
sasho [114]

Answer:

The magnitude of the average force exerted by the club on the ball during contact = mv/t

Explanation:

Impulse exerted on the ball = Momentum of the ball = mass * velocity = m*v

As we know,  

m*v = Integration of F.dt with limits 0 to T

Ft = mv

F = mv/t

The magnitude of the average force exerted by the club on the ball during contact = mv/t

5 0
2 years ago
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