The work done is the product between the intensity of the force applied F, the amount of the displacement d of the book and the cosine of the angle
between the direction of the force and the direction of the displacement:
In our problem, the student is lifting the book, so he is applying a force directed upward, and the book is moving upward, so F and d are parallel and therefore the angle is zero, so
Therefore, the work done is
Answer:
Hello there use something that looks like this
Explanation:
This is an accurate representation of something you are working on!
As you can see the wire and the core are represented on the left and is showing how it can be represented on your right hand and how they are similar!
Answer: The final volume V₂ of the container is 0.039 m³.
Explanation:
Since the temperature is constant, the gas would expand isothermally.
For isothermal expansion,
P₁V₁=P₂V₂
Where, P₁ and P₂ are the initial and final pressure and V₁ and V₂ are initial and final volume.
It is given that:
V₁ = 0.0250 m³
P₁ = 1.5 × 10⁶ Pa
P₂ = 0.950 × 10⁶ Pa
V₂ = ?
⇒ 1.5 × 10⁶ Pa × 0.0250 m³ = 0.950 × 10⁶ Pa × V₂
⇒V₂ = 0.039 m³
Hence, the final volume V₂ of the container is 0.039 m³.
Answer:
The partial pressure of H2 is 0.375 atm
The partial pressure of Ne is also 0.375 atm
Explanation:
Mass of H2 = 1 g
Mass of Ne = 1 g
Mass of Ar = 1 g
Mass of Kr = 1 g
Total mass of gas mixture = 1 + 1 + 1 + 1 = 4 g
Pressure of sealed container = 1.5 atm
Partial pressure of H2 = (mass of H2/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm
Partial pressure of Ne = (mass of Ne/total mass of gas mixture) × pressure of sealed container = 1/4 × 1.5 = 0.375 atm
