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bezimeni [28]
2 years ago
10

The_method is the safest turning technique to use as it does not

Physics
2 answers:
masha68 [24]2 years ago
4 0

Answer: A.

Explanation:

Ilya [14]2 years ago
3 0

Answer:

The correct answer is A. The push/pull also known as hand-to-hand technique

Explanation:

A. <em>PUSH/ PULL STEERING (HAND-TO-HAND)</em>

This is the correct answer. The push/pull turn is also known as the hand-to-hand can be done such that your hands never cross over the steering wheel. Since the hands do not cross over the steering wheel, there is less chance of an injury to the face, hands or arms induced by your hands or arms in the event of a frontal crash due to an airbag. This technique has three methods;

The 10 and 2 position

The 9 and 3 position

The 8 and 4 position

Of the three methods, the 9 and 3 position is the preferred method of steering. Two and 10 o’clock is not recommended because it can be dangerous in vehicles with smaller steering wheels and equipped with airbags.

B. <em>SECURE TURN</em>

This option is wrong. It is not safe as regards to airbag deployment

C. <em>HAND-OVER-HAND STEERING</em>

This option is wrong. This method of steering is used when turning at low speeds with limited visibility at an intersection or when parking the vehicle or recovering from a skid. In hand-over-hand steering, the driver’s arms will pass across the airbag deployment zone. In the event of an airbag deployment, the driver arms will be thrown back into his face.

D. <em>THE THREE POINT TURN</em>

This option is wrong. It is a method you use when you want to execute a U-turn and you can only do it in limited place when the road is free of traffic. It should not be done near a main road, near a short curve, near an intersection or near the crest of a hill

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Explanation:

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3 years ago
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A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50 . A 20-
andreyandreev [35.5K]

The resultant static friction force is equal to 20 N to the left.

Why?

I'm assuming that you forgot to write the question of the exercise, so,  I will try to complete it:

"A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50 . A 20-n force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?"

So, if we are going to calculate the resulting static friction force, it means that there is no movement, we must remember that the friction coefficient will give us the maximum force before the crate starts to move.

We can calculate the static friction force by using the following formula:

Fr=F(appliedforce)

Since the crate is not moving (static), the static friction force acting on the crate will be equal to the applied force.

Calculating we have:

Fr=F(appliedforce)

Fr=20N

Hence, the static friction force is equal to 20 N to the left (since the applied force is acting to the right)

So,

FrictionForce=AppliedForce

Since the static friction force is equal to the applied force, the crate does not start to move.

Have a nice day!

8 0
2 years ago
a 2 meter tall astronaut standing on mars drops her glasses from her nose. how long will the astronaut have before he hits the g
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Here,
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Gravity on mars (g) = 3.7m/s^2
Initial velocity (u) = 0 m/s^2
By the one of the formula of the motion,
S = ut + 1/2at^2
2 = 0 * t + 1/2*3.7*t^2
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So, it will take 1.03s long..

7 0
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At a certain instant after jumping from the airplane A, a skydiver B is in the position shown and has reached a terminal (consta
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Answer:

a=2330

b= 0.223secs

Explanation:

pb=2330m

t=0.223secs

6 0
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