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gayaneshka [121]
2 years ago
7

A solution at 25 ∘C has pOH = 10.53. Which of the following statements is or are true? The solution is acidic. The pH of the sol

ution is 14.00 - 10.53. For this solution, [OH−] = 10−10.53 M.
Chemistry
1 answer:
Lady bird [3.3K]2 years ago
8 0

Answer:

The true statements are:

The solution is acidic

The pH of the solution is 14.00 - 10.53.

10^{-10.53}=[OH^-]

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ion concentration present in the solution .

pH=-\log[H^+]

  • The pH value more 7 means that hydrogen ion concentration is less ,alkaline will be the solution.
  • The pH value less 7 means that hydrogen ion concentration is more ,acidic will be the solution.
  • The pH value equal to 7 indicates that the solution is neutral.

The pOH of the solution is defined as negative logarithm of hydroxide ion concentration present in the solution .

pOH=-\log[OH^-]

The pOH of the solution = 10.53

10.53=-\log[OH^-]

10^{-10.53}=[OH^-]

The pH of the solution = ?

pH+pOH=14

pH=14-pOH=14-10.53=3.47

Here, the pH of the solution is less than 7 which means that solution acidic.

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JulsSmile [24]
Ok so this is what we know :

2KClO3 -> 2KCl + 3O2         (Always check if equation is balanced - in this                                               case it is)
                              4.26moles
So we know that we have 4.26 moles of oxygen (O2). Now lets look at the ratio between KClO3 and O2.
We see that the ratio is 2:3 meaning that we need 2KClO3 in order to produce 3O2.
Therefore divide 4.26 by 3 and then multiply by 2.
4.26/3 = 1.42
1.42 * 2 = 2.84
Now we know that the molarity of KClO3 is 2.84 moles.
Multiply by R.M.M to find how many grams of KClO3 we have.

R.M.M of KClO3
K- 39
Cl- 35.5
3O- 3 * 16 -> 48
---------------------------
                      <span>122.5
</span>2.84 * 122.5 = 347.9 grams therefore the answer is (a)
                       348 grams needed of KClO3 to produce 4.26 moles of O2.
Hope this helps :).

8 0
2 years ago
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The average kinetic energy of water molecules is greatest in which of these samples?(1) 10 g of water at 35°C(2) 10 g of water a
Ipatiy [6.2K]
The question asks about the average kinetic energy so it is not related with mass. We only need to compare the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (2).
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Which statement is correct? Salts are formed by the reaction of bases with water. Most salts are ionic and are soluble in water.
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<span>Salts are formed by the reaction of bases with water. -  FALSE
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3 0
2 years ago
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Q1) A vapor-compression refrigeration system operates on the cycle of Fig. 9.1. The refrigerant is 1,1,1,2-Tetrafluoroethane. Gi
hoa [83]

Answer:

i)   0.5071 (kg/s)

ii)  -1407.1 kj/kg

iii)  204.05 Kw

iv)  5.881

v)    9.238

Explanation:

Given Data:

evaporation temperature ( T ) = 4°c = 277.15 K

Condensation Temperature ( T ) = 34°c = 307.15 K

<em>n</em> ( compressor efficiency ) = 0.76

refrigeration rate = 1200 kJ.s^-1

i) determine the circulation rate of the refrigerant

m = \frac{Q}{H2 - H1}  = \frac{Q}{H2 - H4\\}  ------- 1

Q = 1200 Kj.s^-1

H2 = entropy at step 2 = 2508.9 (kJ / kg ) ( gotten from Table F )

H4 = entropy at step 4 = 142.4 ( kJ/ kg )

back to equation 1

m ( circulation rate of refrigerant ) = 0.5071 (kg/s)

ii) heat transfer rate in the condenser

Q = m ( H4 - H3 )

    = 0.5071 ( 142.4 - 2911.27 )

    = -1407.1 kj/kg

where H3 = H2 + ΔH23 = 2911.27 (kj/kg) ( as calculated )

iii) power requirement

w = m * ΔH23

   = 0.5071 (kg/s) * 402.37 (kj/kg) =  204.05 Kw

where: ΔH23 = \frac{H'3 - H2 }{0.76} = \frac{2814.7-2508.9}{0.76} = 402.37 (kj/kg)

iv) coefficient of performance of a cycle

W = Qc / w

  = 1200 Kj.s^-1/ 204.05 kw

  = 5.881

v) coefficient of performance of a Carnot refrigeration cycle

w_{carnot} = \frac{T2}{T4 - T2}

            =  277.15 / ( 307.15 - 277.15 )

            = 9.238

4 0
2 years ago
A gas is initially at a pressure of 0.43 atm, and a volume of 11.7 liters. Then the pressure is raised to 3.61 atm and the volum
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Answer:

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Explanation:

The General Gas Law equation is given by,

\frac{P_1V_1}{T_1}  =  \frac{P_2V_2}{T_2}

From the question,

the initial pressure,

P_1 = 0.43 \: atm

the initial volume,

V_1 = 11.7 \: litres

the final temperature,

T_2=627K

the final pressure,

P_2=3.61atm

the final volume,

V_2=9.5litres

Making

T_1

the subject of the expression, we obtain

T_1= \frac{P_1V_1T_2}{P_2V_2}

By substitution,

T_1= \frac{0.43 \times11.7 \times627}{3.61 \times9.5}

T_1=91.980K

Hence the initial temperature was 91.98 K

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2 years ago
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