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DanielleElmas [232]
2 years ago
7

Paintball is a popular recreational activity that uses a metal tank of compressed carbon dioxide or nitrogen to launch small cap

sules of paint. A typical tank has a volume of 508 cubic centimeters. A 340. gram sample of carbon dioxide is added to the tank before it is used for paintball. At 20.oC, this tank contains both CO2(g) and CO2(l). After a paintball game, the tank contains only CO2(g).
Determine the total number of moles of CO2 added to the tank before it is used for paintball.
Chemistry
1 answer:
irinina [24]2 years ago
6 0
We know,
1000 cm³ = 1 L
1 cm³ = 1 / 1000 L
508 cm³ = (1 / 1000) * 508 L = 0.5080 L

So, 508 cm³ = 0.5080 L

Now,
We know,
22.4 L = 1 mole
1 L = 1 / 22.4 mole
0.5080 L = (1 / 22.4) * 0.5080L = 0.0227 moles

So, 0.0277 moles  moles of CO_2 are added to the tank before it is used for paintball.
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When C2H5Cl(g) is burned in oxygen, chlorine gas is produced in addition to carbon dioxide and water vapor. 5145 kJ of heat are
Arisa [49]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

\text{hydrocarbon}+O_2\rightarrow CO_2+H_2O

The chemical equation for the combustion of ethyl chloride follows:

4C_2H_5Cl+13O_2\rightarrow 2Cl_2+8CO_2+10H_2O

We are given:

When 4 moles of ethyl chloride is burnt, 5145 kJ of heat is released.

For an endothermic reaction, heat is getting absorbed during a chemical reaction and is written on the reactant side.

A+\text{heat}\rightleftharpoons B

For an exothermic reaction, heat is getting released during a chemical reaction and is written on the product side

A\rightleftharpoons B+\text{heat}

So, the chemical equation follows:

4C_2H_5Cl+13O_2\rightarrow 2Cl_2+8CO_2+10H_2O+5145kJ

Hence, the chemical equation is written above.

7 0
2 years ago
How would each of the following procedural errors affect the results to be expected in this experiment? Give your reasoning in e
Digiron [165]

Answer:

a) if the liquid is not vaporized completely, then the condensed vapor in the flask contains the air which is initially occupied before the liquid is heated. When calculating the molar mass of the vapor the moles of air which are initially present are not excluded, so that the molar mass of the vapor would be an increase in value.

b) While weighing the condensed vapor, the flask should be dried. If the weighing flask is not dried then the water which is layered on the surface of the flask is also added to the mass of the vapor. Therefore, the mass of the vapor that is calculated would be increase.

c) When condensing the vapor, the stopper should not be removed from the flask, because the vapor will escape from the flask and a small amount of vapor will condense in the flask. Therefore, the mass of the condensed vapor would be In small value.

d) If all the liquid is vaporized, when the flask is removed before the vapor had reached the temperature of boiling water, then the boiling

temperature of that liquid would be lower than that of the boiling temperature of the water.Therefore, the liquid may have more volatility.

7 0
2 years ago
What is the fraction of the hydrogen atom's mass (11h) that is in the nucleus? the mass of proton is 1.007276 u, and the mass of
ololo11 [35]
Hello there!

To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that a Hydrogen atom has 1 proton and 1 electron. Protons are in the nucleus while electrons are in electron shells surrounding the nucleus. The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:

Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995

So, the fraction of the hydrogen atom's mass that is in the nucleus is 0,9995. That means that almost all the mass of this atom is at the nucleus.

Have a nice day!
3 0
2 years ago
The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is __________% by
amm1812

Answer:

The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of 1.01 g/mL is 12.90% by mass

Explanation:

2.23 M aqueous solution of NaCl means there are 2.23 moles of NaCl in 1000 mL of solution.

We know that density is equal to ratio of mass to volume.

Here density of solution is 1.01 g/mL.

So mass of 1000 mL solution = (1.01\times 1000) g = 1010 g

molar mass of NaCl = 58.44 g/mol

So mass of 2.23 moles of NaCl = (2.23\times 58.44) g = 130.3 g

% by mass  is ratio of mass of solute to mass of solution and then  multiplied by 100.

Here solute is NaCl.

So % by mass of 2.23 M aqueous solution of NaCl = \frac{130.0}{1010}\times 100% = 12.90%

3 0
2 years ago
Be sure to answer all parts. liquid ammonia autoionizes like water: 2nh3(l) → nh4+(am) + nh2−(am) where (am) represents solvatio
Genrish500 [490]
Answer is: concentration of ammonium ions are 7,14·10⁻¹⁴ M.
Chemical reaction: 2NH₃(l) → NH₄⁺(am) + NH₂⁻(am).
Kam = 5,1·10⁻²⁷.
[NH₄⁺] · [NH₂⁻] = x; equilibrium concentration of cations and anions.
Kam = [NH₄⁺] · [NH₂⁻].
Kam = x².
x = [NH₄⁺] = √5,1·10⁻²⁷.
[NH₄⁺] = 7,14·10⁻¹⁴ M.

5 0
2 years ago
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