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Elena-2011 [213]
2 years ago
11

A sculptor has asked you to help electroplate gold onto a brass statue. You know that the charge carriers in the ionic solution

are singly ionized gold ions, and you've calculated that you must deposit 0.50 g of gold to reach the necessary thickness. How much current do you need, in mA, to plate the statue in 6.0 hours?
Physics
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

Explanation:

Mass of gold deposited = 0.5 g

Molar mass of gold = 197 g/mol

Time, t = 6 hours

= 6 × 3600

= 12600 s

Number of moles = mass/molar mass

= 0.5/197

= 0.00254 mole

Assuming

Au --> Au+ + e-

Faraday constant = 9.65 x 104 C mol-1

Q = 96500 × 0.00254

= 244.924 C

Q = I × t

I = 244.924/12600

= 0.011 A

= 11.34 mA.

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Answer:

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Explanation:

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2 years ago
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A person is working on a steel structure while standing on the ground. An accident occurred where 5 A pass through the structure
matrenka [14]

Answer:

35mA

Explanation:

Hello!

To solve this problem we must use the following steps

1. Find the electrical resistance of the metal rod using the following equation

R=\alpha  \frac{l}{a}

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α=

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2. Now we model the system as a circuit with parallel resistors, where we will call 1 the metal rod and 2 the man(see attached image)

3.we know that the sum of the currents in 1 and 2 must be equal to 5A, by the law of conservation of energy

I1+I2=5

4.as the voltage on both nodes is the same we can use ohm's law in resitance 1 and 2 (V=IR)

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solving for i1

I1=14285.7i2

5.Now we use the equation found in step 3

14285.7i2+i2=5

i2=\frac{5}{14285.7+1} =3.5x10^-4A=35mA

6 0
2 years ago
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kkurt [141]

Explanation:

the question is unanswerable

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Summary:
m=1kg
a=8 m/s^2
g= 9,8 m/s^2
F(ar)=?


I hope to help you

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