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inn [45]
2 years ago
14

When drawing the Lewis structure for a molecule, after drawing the skeletal structure and distributing all of the electrons arou

nd the the terminal atoms, what actions should be taken if the central atom does not have a complete octet
Chemistry
1 answer:
Ksju [112]2 years ago
7 0

Answer: Rearrange lone pairs of electrons from the outer atom(s) to form double or triple bonds to the central atom.

Explanation:

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To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu
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The answer is <span>D.when the aim is to show electron distributions in shells. This is because there are some instances when elements don't possess a regular or normal electron configuration. There are those who have special electron configurations wherein a lower subshell isn't completely filled before occupying a higher subshell. It is best to visualize such cases using the orbital notation.</span>
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2 years ago
Four balloons, each with a mass of 10.0 g, are inflated to a volume of 20.0 L, each with a different gas: helium, neon, carbon m
weeeeeb [17]
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
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6 0
2 years ago
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What is the density (in g/L) of a gas with a molar mass of 146.06 g/mol at 1.03 atm and 297k
marshall27 [118]
Lets assume the gas is acting Ideally, then According to Ideal Gas Equation the density is given as,

                                            d  =  P M / R T         -------  (1)
Where;
P  = Pressure =  1.03 atm

M  = Molar Mass =  146.06 g/mol

R  = Gas Constant =  0.08206 atm.L.mol⁻¹.K⁻¹

T  = Temperature =   297 K

Putting Values in eq. 1,

           d  =  (1.03 atm × 146.06 g/mol) ÷ (0.08206 atm.L.mol⁻¹.K⁻¹ × 297 K)

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6 0
2 years ago
Write the reduction reaction of glucose to form sorbitol. List and explain the side effects caused by too much sorbitol consumpt
Lemur [1.5K]

Answer:

The product of reduction of glucose is sorbitol

The side effects caused by too much sorbitol consumption include: Diarrhea, Nausea, stomach discomfort

Explanation:

Please find attached the reaction of glucose with NADPH to produce sorbitol

5 0
2 years ago
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