Answer:
Length, l = 33.4 m
Explanation:
Given that,
Electrical field,
Let the electrical potential is,
We need to find the length of a thundercloud lightning bolt. The relation between electric field and the electric potential is given by :
So, the length of a thundercloud lightning bolt is 33.4 meters. Hence, this is the required solution.
Answer:
To both observers, the land opposite them is moving to the right.
Explanation:
I have this class too. and there is also a quizlet with all the answers to the rest of the other questions. Trust me its right .
https://quizlet.com/261219090/oce-1001-chapter-2-flash-cards/
Answer:
600 Ω
Explanation:
when there is no load attached to the generator the circuit is open and zero current flows through the circuit, hence voltage drop across the internal resister is zero.
when 600Ω load is connected current starts flowing through the circuit and some voltage will drop across the internal resister.
voltage across the load resister is 1 V, so the current through it will be:
I=V/R
I=1/600 A= 1.67mA
voltage drop in the internal resister is:
V= input voltage - output voltage
V=2 V-1 V
⇒V=1 V
Now by using ohm's law
R=V/ I
R= (I= 1.67mA, as the resistors are connected in series)
⇒R=600 Ω
Hence Thevinin resistance of the generator is 600Ω.
Answer:
35,79 meters
Explanation:
So, we got an archer, and we got a target. Lets call the distance between this two d.
Now, the archer fires the arrow, that, in a time travels the distance d with a speed
of 40 m/s and hits the target. We can see that the equation will be:
Immediately after this, the arrow produces a muffled sound, which will travel the distance d at 340 m/s in a time . Obtaining :
.
Finally, the sound reaches the archer, exactly 1 second after he fired the bow, so:
.
This equation allows us to write:
.
Plugging this relationship in the distance equation for the sound:
.
Now, we can replace d from the first equation, and obtain:
.
Now, we can just work a little bit:
.
Now, we can just plug this value into the first equation: