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julia-pushkina [17]
2 years ago
7

The diagram shows a lever. A bar sits on top of a brown triangle with a black weight at the left end and a finger pushing on the

bar at the right end. Dotted lines run above and parallel with the bar and vertically from the above dotted line to the center of the weight, the point where the triangle meets the bar, and the finger. The distance from the center of the weight to the point of the triangle is labeled 3 meters. The distance from the point of the triangle to the finger is labeled 6 meters. The mechanical advantage of the lever is
Physics
2 answers:
Masteriza [31]2 years ago
7 0

Answer:

2

Explanation:

when talking about the advantage of a lever you take both numbers and divide them to get the correct answer.  3/6 = 2

Elden [556K]2 years ago
3 0

Answer:

2

Explanation:

took the test

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A steel cylinder at sea level contains air at a high pressure. Attached to the tank are two gauges, one that reads absolute pres
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Answer:

C) The pressure reading stays the same.

Explanation:

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Derive an expression for the total mechanical energy of the system as the monkey reaches the top of the motion, Etop, in terms o
ipn [44]

Answer:

U =  0.5 * k *(x + d - h_max)^2 + m*g*h_max

Explanation:

Given:

- The extension in spring @ equilibrium = x m

- The spring constant = k

- The amount of distance pulled down = d

- mass of the toy = m

Find:

- The total mechanical energy E_top at the top position h_max in terms of the available variables.

Solution:

- First we need to determine the types of Energy that are in play:

- The Elastic potential Energy E_p in a spring is given:

                              E_p: 0.5 * k * (ext)

- In our case when the toy at the top most position h_max will have a net extension ext, by summing displacement of spring:

             ext = Equilibrium + distance pulled - h_max = (x + d - h_max)

Hence, the elastic potential energy will be:

                              E_p = 0.5 * k *(x + d - h_max)^2

- The gravitational potential energy E_g is given by:

                              E_g = m*g*h_max

Where, bottom most position is taken as reference (datum).

- The kinetic Energy E_k is given by:

                              E_k = 0.5*m*v_top^2

- Since we know that the maximum height is reached when velocity is zero

Hence,                   E_k = 0.5*m*0^2 = 0.

The total Energy of the system U is sum of all energies and play:

                               U = E_p + E_k + E_g

                               U =  0.5 * k *(x + d - h_max)^2 + m*g*h_max

8 0
2 years ago
Every spring has an equilibrium position. Which statements describe a spring at its equilibrium position? Check all that
alexgriva [62]

Answer:

The elastic potential energy is zero.

The net force acting on the spring is zero.

Explanation:

The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.

Let's now analyze the different statements:

The spring constant is zero.  --> false. The spring constant is never zero.

The elastic potential energy is at a maximum  --> false. The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where k is the spring constant and x the displacement. Therefore, the elastic potential energy is maximum when x, the displacement, is maximum.

The elastic potential energy is zero.  --> true. As we saw from the equation above, the elastic potential energy is zero when the displacement is zero (at the equilibrium position).

The displacement of the spring is at a maxi num  --> false, for what we said above

The net force acting on the spring is zero. --> true, as the spring is neither compressed nor stretched

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The image shows a pendulum that is released from rest at point A. Shari tells her friend that no energy transformation occurs as
Masja [62]
Is  D    the  right  answer
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A uniform magnetic field of 0.50 T is directed along the positive x axis. A proton moving with a speed of 60 km s enters this fi
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Explanation:

It is given that,

Magnetic field, B = 0.5 T

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The helical path followed by the proton shown has a pitch of 5.0 mm, p = 0.005 m

We need to find the  angle between the magnetic field and the velocity of the proton. The pitch of the helix is the product of parallel component of velocity and time period. Mathematically, it is given by :

p=v_{||}\times T

p=v\ cos\theta\times \dfrac{2\pi m}{Bq}

cos\theta=\dfrac{pBq}{2\pi mv}

cos\theta=\dfrac{0.005\times 0.5\times 1.6\times 10^{-19}}{2\pi \times 1.67\times 10^{-27}\times 60000}

\theta=50.58^{\circ}

So, the angle between the magnetic field and the velocity of the proton is 50.58 degrees. Hence, this is the required solution.

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