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Kay [80]
2 years ago
7

To understand the forces between a bar magnet and 1. a stationary charge, 2. a moving charge, and 3. a ferromagnetic object. A b

ar magnet oriented along the y axis can rotate about an axis parallel to the z axis. Its north pole initially points along j^.
Physics
1 answer:
Brums [2.3K]2 years ago
3 0

Answer:

Explanation:

1. If the charge is stationary and it is not moving, then the magnetic force will be zero, since the velocity is 0m/s

From the formula of magnetic force

F = q(V×B)

And since V is 0, then, the magnetic force is zero

F = 0N,

No torque at all.

2. The moving charge interacts with the fixed magnet. The force between them is at a maximum when the velocity of the charge is perpendicular to the magnetic field.

From the formula of magnetic force

F = q( V×B)

V × B = |V|•|B| Sinθ

So, Sinθ has its highest value at 90° in the range of 0-360°

So, the force will have a maximum value when the moving charge is perpendicular to the magnetic field

Now, since the magnetic field is in the positive y-direction, for the force to be maximum the electron must move the positive x-direction.

So the force will be in the positive z-direction(since i×j= k).

3. Now, the charge is replaced by an electrically neutral piece of initially unmagnetized soft iron (e.g. nail) that is not moving. This result into the magnetic experience a force due to the iron fillings attracting its north pole.

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An object is dropped from rest into a pit, and accelerates due to gravity at roughly 10 m/s2. It hits the ground in 5 seconds. A
vitfil [10]

Answer:

Second pit is 375 m deeper compared to first pit.

Explanation:

We have equation of motion s = ut + 0.5at²

First object hits the ground after 5 seconds,

          Initial velocity, u = 0 m/s

         Acceleration, a = 10 m/s²

         Time, t = 5 s

    Substituting,

                  s = ut + 0.5 at²

                 s = 0 x 5 + 0.5 x 10 x 5²

                    s = 125 m

           Depth of pit 1 = 125 m

Second object hits the ground after 10 seconds,

          Initial velocity, u = 0 m/s

         Acceleration, a = 10 m/s²

         Time, t = 10 s

    Substituting,

                  s = ut + 0.5 at²

                 s = 0 x 10 + 0.5 x 10 x 10²

                    s = 500 m

           Depth of pit 2 = 500 m

Difference in depths = 500 - 125 = 375 m

Second pit is 375 m deeper compared to first pit.

7 0
2 years ago
When the particles of a medium move with simple harmonic motion, this means the wave is a __________. when the particles of a me
san4es73 [151]
<span>When the particles of a medium move with simple harmonic motion, this means the wave is a sinusoidal wave.

Know that a sinusoidal curve can describe either sine or cosine functions (remember your cofunction identities for sine and cosine).</span>
6 0
2 years ago
Read 2 more answers
Suppose Earth's mass increased but Earth's diame-
navik [9.2K]

Answer: It would increase.

Explanation:

The equation for determining the force of the gravitational pull between any two objects is:

F = G \frac{m1m2}{r^2}

Where G is the universal gravitational constant, m1 is the mass of one body, m2 is the mass of the other body, and r^2 is the distance between the two objects' centers squared.

Assuming the Earth's mass but not its diameter increased, in the equation above m1 (the term usually indicative of the object of larger mass) would increase, while the r^2 would not.

Thus, it goes without saying that, with some simple reasoning about fractions, an increasing numerator over a constant denominator would result in a larger number to multiply by G, thus also meaning a larger gravitational strength between Earth and whatever other object is of interest.

7 0
2 years ago
he first excited state of the helium atom lies at an energy 19.82 eV above the ground state. If this excited state is three-fold
bekas [8.4K]

Answer:

Relative population is  2.94 x 10⁻¹⁰.

Explanation:

Let N₁ and N₂ be the number of atoms at ground and first excited state of helium respectively and E₁ and E₂ be the ground and first excited state energy of helium respectively.

The ratio of population of atoms as a function of energy and temperature is known as Boltzmann Equation. The equation is:

\frac{N_{1} }{N_{2} } =  \frac{g_{1}e^{\frac{-E_{1} }{KT} }  }{g_{2}e^{\frac{-E_{2} }{KT} }}

\frac{N_{1} }{N_{2} } = \frac{g_{1}e^{\frac{-(E_{1}-E_{2})  }{KT} }  }{g_{2}}

Here g₁ and g₂ be the degeneracy at two levels, K is Boltzmann constant and T is equilibrium temperature.

Put 1 for g₁, 3 for g₂, -19.82 ev for (E₁ - E₂) and 8.6x10⁵ ev/K for K and 10000 k for T in the above equation.

\frac{N_{1} }{N_{2} } = \frac{1\times e^{\frac{-(-19.82)}{8.6\times 10^{-5}\times 10000} }  }{3}

\frac{N_{1} }{N_{2} } = 3.4 x 10⁹

\frac{N_{2} }{N_{1} } =  2.94 x 10⁻¹⁰

5 0
2 years ago
A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through
Svet_ta [14]

Answer:

The speed is \sqrt{2}v_{0}.

(a) is correct option.

Explanation:

Given that,

Potential difference V= V_{0}

Speed v = v_{o}

If it were accelerated instead

Potential difference V'=2V_{0}

We need to calculate the speed

Using formula of initial work done on proton

W = q V

We know that,

\Delta W=\Delta K.E

q V=\dfrac{1}{2}mv^2

Put the value into the formula

q V_{0}=\dfrac{1}{2}mv_{0}^2

v_{0}^2=\dfrac{2qV_{0}}{m}....(I)

If it were accelerated instead through a potential difference of 2 V_{0}, then it would gain a speed will be given as :

Using an above formula,

v_{0}'^2=\dfrac{2qV_{0}}{m}

Put the value of V_{0}

v_{0}'^2=\dfrac{2q\times2V_{0}}{m}

v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}

v_{0}'=\sqrt{2}v_{0}

Hence, The speed is \sqrt{2}v_{0}.

6 0
2 years ago
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