As new-forming stars grow by gravitationally attracting more material, they become brighter. If a star becomes too bright, the r
2 answers:
Answer:
The power output of the star is 2.215x10²⁸W
Explanation:
Given data:
ms = mass of the star = 35.135 times msun
rp = radius = 0.935 mm = 9.35x10⁻⁴m
p = 3.46 μg = 3.46x10⁻⁹g
msun = mass of the Sun = 1.99x10³⁰kg
G = gravitational constant = 6.67x10⁻¹¹m³/kg s²
c = speed of light = 3x10⁸m/s
Question: What power ouput would a star, P = ?
First, calculate the mass of the star:
The power output of the star:
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Answer:
ΔH°comb=-5899.5 kJ/mol
Explanation:
First, consider the energy balance:
Where
is the calorimeter mass and
is the number of moles of the samples;
is the combustion enthalpy. The energy balance says that the energy that the reaction release is employed in rise the temperature of the calorimeter, which is designed to be adiabatic, so it is suppose that the total energy is employed rising the calorimeter temperature.
The product is the heat capacity, so the balance equation is:
So, the enthalpy of combustion can be calculated:
I will be happy to solve any doubt you have.
To solve this problem we will use the trigonometric concepts to find the distance h, which will allow us to find the speed of Jeff and that will finally be the variable that will indicate the total tension, since it is the variable of the centrifugal Force given in the vine at the lowest poing of the swing.
From the image:
When Jeff reaches his lowest point his potential energy is converted to kinetic energy
Tension in the string at the lowest point is sum of weight of Jeff and the his centripetal force
Therefore the tension in the vine at the lowest point of the swing is 842.49N
Answer:
<h2>Center of gravity of the system of all masses is 105 cm from the left end of the rod</h2>Explanation:
Let the position of Left end of the rod is our reference
So here we will have
so we will have