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Naya [18.7K]
2 years ago
12

Limes have a [H3O+] of 1.3 x 10-2 mol/L. Their pOH is​

Chemistry
1 answer:
sweet-ann [11.9K]2 years ago
4 0
To determine the pOH assuming water is the universal solvent take the value of 10 ^ -14 and then divide it by the hydronium concentration and then take the negative logarithm of the final answer that is the solution to the hydroxide ion concentration in the solution.
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A saturated solution of potassium iodide contains, in each 100 mL, 100 g of potassium iodide. The solubility of potassium iodide
Oksanka [162]

Answer:

Specific gravity of the saturated solution is 2

Explanation:

The specific gravity is defined as the ratio between density of a solution (In this case, saturated solution of potassium iodide, KI) and the density of water. Assuming density of water is 1:

Specific gravity  = Density

The density is the ratio between the mass of the solution and its volume.

In 100mL of water, the mass of KI that can be dissolved is:

100mL * (1g KI / 0.7mL) = 143g of KI

That means all the 100g of KI are dissolved (Mass solute)

As the volume of water is 100mL, the mass is 100g (Mass solvent)

The mass of the solution is 100g + 100g = 200g

In a volume of 100mL, the density of the solution is:

200g / 100mL = 2g/mL.

The specific gravity has no units, that means specific gravity of the saturated solution is 2

5 0
1 year ago
A 100 mL reaction vessel initially contains 2.60×10^-2 moles of NO and 1.30×10^-2 moles of H2. At equilibrium the concentration
Sliva [168]

Answer:

<h2>The equilibrium constant Kc for this reaction is 19.4760</h2>

Explanation:

The volume of vessel used= 100 ml

Initial moles of NO= \frac{2.60}{10^2} moles

Initial moles of H2= \frac{1.30}{10^2} moles

Concentration of NO at equilibrium= 0.161M

Concentration(in M)=\frac{moles}{volume(in litre)}

Moles of NO at equilibrium= 0.161(\frac{100}{1000})

                                            =\frac{1.61}{10^2} moles

               

                    2H2 (g)        +    2NO(g) <—>    2H2O (g) +    N2 (g)

<u>Initial</u>          :1.3*10^-2          2.6*10^-2                0                   0        moles

<u>Equilibrium</u>:1.3*10^-2 - x     2.6*10^-2-x              x                   x/2     moles

∴\frac{2.60}{10^2}-x=\frac{1.61}{10^2}

⇒x=\frac{0.99}{10^2}

Kc=\frac{[H2O]^2[N2]}{[H2]^2[NO]^2} (volume of vesselin litre)

<u>Equilibrium</u>:0.31*10^-2      1.61*10^-2          0.99*10^-2        0.495*10^-2  moles

⇒Kc=\frac{(0.0099)^2(0.00495)}{(0.0031)^2(0.0161)^2}  (0.1)

⇒Kc=19.4760

3 0
2 years ago
Industrial production of nitric acid, which is used in many products including fertilizers and explosives, approaches 10 billion
mylen [45]

Answer: 9.361\times 10^{4} kJ

Explanation:

The balanced chemical equation :

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)  \Delta H^0_{rxn}=-902.0kJ

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{7.056\times 10^3g}{17g/mol}=415.1moles

According to stoichiometry:

4 moles of NH_3 produces = 902.0 kJ of energy

415.1 moles of NH_3 produces =\frac{902.0}{4}\times 415.1=9.361\times 10^{4} kJ of energy

Thus the change in enthalpy is 9.361\times 10^{4} kJ

5 0
2 years ago
Imagine that a chemist is trying to establish whether a piece of rock is from a meteorite that fell from outer space. the rock c
rusak2 [61]
The sample is likely to be from a meteorite.

The reason for this is the fact that the isotope Copper-63 is more abundant on planet Earth than the isotope Copper-65 is. Therefore, if a sample of rock has Cu-65 in a greater quantity, it is likely to be from outer space. Many other elements entered the Earth's crust as a result of meteorite impacts, such as Iron (Fe).
8 0
2 years ago
A molecular orbital is a region of space in a covalent species where electrons are likely to be found. The combination of two at
lara [203]

Answer:

bonding molecular orbital is lower in energy

antibonding molecular orbital is higher in energy

Explanation:

Electrons in bonding molecular orbitals help to hold the positively charged nuclei together, and they are always lower in energy than the original atomic orbitals.

Electrons in antibonding molecular orbitals are primarily located outside the internuclear region, leading to increased repulsions between the positively charged nuclei. They are always higher in energy than the parent atomic orbitals.

5 0
1 year ago
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